IE121-OLA3 3rdQ 1516 answers
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<strong>IE121</strong> – OLA 3<br />
<strong>3rdQ</strong> 2015 – 2016<br />
<strong>OLA3</strong> Stat1 Answer Key<br />
Binomial b(x; n, p) = nC x x (P) x x (1-P) n-x<br />
Hypergeometric h(x; N, n, k) = [ kC x ] [ N-kC n-x ] / [ NC n ]<br />
Poisson P(; x) = (e -μ ) (μ x ) / x!<br />
1. Suppose that a shipment contains 5 defective items and 10 non defective items. If 7 items are<br />
selected at random without replacement, what is the probability that at least 3 defective items will<br />
be obtained? (10pts)<br />
ANS: h(x; N, n, k) = h(x2) = 1 – P(0) + P(1) + P(2) = 1-0.5734 = 0.4266<br />
2. The mean number of cracks in South Super Highway that needs repair is 2 cracks per kilometer.<br />
a. What is the probability there are at most 4 cracks that requires repair for every 3 kilometers?<br />
b. What is the probability that at least one crack requires repair in 2 kilometers of highway? (5pts)<br />
ANS:<br />
a. P(; x) = (e -μ ) (μ x ) / x!<br />
P(6; x=4) = 1 - (e -4 ) (4 0 ) / 0! = 0.9817<br />
3. If the probability that a regular LED bulb has a useful life of at least 1,000 hours is 0.9, find the<br />
probabilities that among 20 such lights<br />
a. at least 15 will have a useful life of at least 1000 hours. (5pts)<br />
b. at least 2 will not have a useful life of at least 1000 hours. (5pts)<br />
ANS: a. b(x>=15; 20, 0.9) = 0.9888<br />
b. b(x>=2; 20, 0.9) = 1 – 0.3917 =0.6083<br />
4. An acceptance plan calls for the inspection of a sample of 75 articles out of a lot of 1500. If there<br />
are no nonconforming articles in the sample, the lot is accepted; otherwise, it is rejected.<br />
a. Find the probability that if a lot of 1% nonconforming is submitted, it will be accepted. (10pts)<br />
b. If a lot containing 2% nonconforming is inspected, what is the probability that it will be<br />
rejected? (20pts)<br />
ANS: Binomial b(x; n, p) = nCx x (P) x x (1-P) n-x<br />
a. b(0, 75, 0.01) = 0.4706<br />
b. b(0, 75, 0.02) = 0.2198 accepted<br />
b(0, 75, 0.02) = 1-0.2198 = 0.7082 rejected<br />
5. Nokia usually placed their phones in a functional test after being populated with semiconductor<br />
chips. 1 batch contains 3000 cellphones, and 20 are selected without replacement for functional<br />
testing.
a. What is the probability that at most 1 defective cellphone is in the sample if 30 cards are<br />
defective? (10pts)<br />
b. What is the probability that at least 1 defective cellphone appears in the sample if 90 cards are<br />
defective? (10pts)<br />
ANS: a. h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]<br />
h(x≤1; 3000, 20, 30) = [ 30C0 ] [ 3000-30C20-0 ] / [ 3000C20 ] + [ 30C1 ] [ 3000-30C20-1 ] / [ 3000C20 ]<br />
h(x≤1; 3000, 20, 30) = 0.8174 + 0.1662 = 0.9836<br />
b. h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]<br />
h(x≥1; 3000, 20, 90) = 1 – [ 90C0 ] [ 3000-90C20-0 ] / [ 3000C90 ]<br />
h(x≥1; 3000, 20, 90) = 1 – 0.5427 = 0.4573<br />
6. Mars Inc. claims that 20% of its M&M plain candies are blue, and a sample of 100 such candies is<br />
randomly selected.<br />
a. Find the mean and standard deviation for the number of blue candies in such sample of 100.<br />
(5pts)<br />
b. From range rule of thumb, any result is considered unusual if it differs by more than two<br />
standard deviation from the mean. If a sample of 100 M&M plain candies only has 5 blue<br />
candies, is this result unusual? Does it seem that the claim rate of 20% is wrong? (5pts)<br />
a. Mean μ = np = 100 (0.20) = 20.0<br />
Standard deviation σ = =<br />
= 4<br />
b. Using range rule of thumb, the unusual values are<br />
< μ – 2σ = 20.0 – 2(4.0) = 12<br />
Or > μ + 2σ = 20.0 + 2(4.0) = 28<br />
** It is unusual for the pack of M&M candies to have blue candies lower than 12.<br />
npq<br />
100(0.20) (0.80)<br />
5. Suppose on the average, 1 out of 20 students cannot answer this question correctly. If 40 of this<br />
kind of question are selected at random and checked, find the probability that<br />
a. 4,5 or 6 questions will be answered incorrectly.<br />
b. more than 2 questions will be answered incorrectly.<br />
ANS: p = 1/20 n = 40 = 1/20 (40) = 2<br />
a. P(2; 4