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SPA 3e_ Teachers Edition _ Ch 6

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418<br />

C H A P T E R 6 • Sampling Distributions<br />

Teaching Tip<br />

The rule of thumb mentioned here is<br />

sometimes called the 10% condition. As<br />

long as the sample size is less than 10%<br />

of the population size, the sample count<br />

will have a distribution that is close<br />

enough to a binomial distribution that<br />

binomial probabilities will be reasonably<br />

accurate.<br />

Teaching Tip<br />

Remind students that the mean is also<br />

called the expected value!<br />

In practice, we can ignore the violation of the independence condition caused by<br />

sampling without replacement whenever the sample size is relatively small compared<br />

to the population size. Specifically, we can assume that the sampling distribution of a<br />

sample count X is approximately binomial when the sample size is less than 10% of<br />

the population size.<br />

Center and Variability<br />

Because the sampling distribution of a sample count X is approximately binomial<br />

when the sample is a small fraction of the population, we can use the formulas from<br />

Lesson 5.4 to calculate the mean and standard deviation of X.<br />

How to Calculate μ x and σ x for a Binomial Distribution<br />

Suppose X is the number of successes in a random sample of size n from a large population<br />

with proportion of successes p. Then:<br />

• The mean of the sampling distribution of X is m X = np.<br />

• The standard deviation of the sampling distribution of X is s X = "np(1 − p).<br />

The formula for the mean is always correct, even if we are sampling without<br />

replacement. However, the formula for the standard deviation is not appropriate to<br />

use when the sample size is more than 10% of the population size.<br />

Alternate Example<br />

Rubber ducky, are you the one?<br />

Mean and SD of the sampling<br />

distribution of X<br />

PROBLEM: A popular carnival game<br />

has players choose a rubber duck from<br />

a small pool and look under the duck.<br />

If a special mark is on the duck, the<br />

player wins a prize. Suppose that a pool<br />

has 5000 ducks, 800 of which have the<br />

special mark. One generous father pays<br />

for his children to choose 20 rubber<br />

ducks. Let X 5 the number of ducks with<br />

the mark in the sample of 20.<br />

(a) Calculate the mean and standard<br />

deviation of the sampling distribution of X.<br />

(b) Interpret the standard deviation<br />

from part (a).<br />

a<br />

e XAMPLe<br />

How many flash drives are defective?<br />

Mean and SD of the sampling distribution of X<br />

PROBLEM: Two percent of the flash drives in a shipment of 10,000 flash drives are defective. An<br />

inspector randomly selects 10 flash drives from the shipment and records X 5 the number of<br />

defective flash drives in the sample.<br />

(a) Calculate the mean and standard deviation of the sampling distribution of X.<br />

(b) Interpret the standard deviation from part (a).<br />

SOLUTION:<br />

(a) m x = 10(0.02) = 0.2 flash drives<br />

s x = "10(0.02)(1 − 0.02) = 0.44 f lash drives<br />

(b) If the inspector took many samples of size 10, the number of<br />

defective flash drives would typically vary by about 0.44 from<br />

the mean of 0.2.<br />

Because the sample size is less than 10% of the<br />

population size, the distribution of X is approximately<br />

binomial with n 5 10 and p 5 0.2. The mean is m X = np<br />

and the standard deviation is s X = "np(1 − p).<br />

FOR PRACTICE TRY EXERCISE 1.<br />

SOLUTION:<br />

(a) m X = 20a 800 b = 20(0.16) = 3.2<br />

5000<br />

ducks with the mark<br />

s X = "20(0.16)(1 − 0.16) = 1.64 ducks<br />

with the mark<br />

(b) If the children took many samples<br />

of 20 ducks, the number of ducks with<br />

the mark would typically vary by about<br />

1.64 from the mean of 3.2.<br />

Starnes_<strong>3e</strong>_CH06_398-449_Final.indd 418<br />

Teaching Tip<br />

The interpretation of the mean and standard<br />

deviation in the preceding example is the<br />

same as in past chapters. Connect the ideas of<br />

past lessons to the current one!<br />

18/08/16 5:00 PMStarnes_<strong>3e</strong>_CH0<br />

418<br />

C H A P T E R 6 • Sampling Distributions<br />

Starnes_<strong>3e</strong>_ATE_CH06_398-449_v3.indd 418<br />

11/01/17 3:55 PM

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