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SPA 3e_ Teachers Edition _ Ch 6

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408<br />

C H A P T E R 6 • Sampling Distributions<br />

14. (a) Population: All guppies at the<br />

pet store. Parameter: m 5 the true mean<br />

length of the population. Sample: A<br />

random sample of 10 guppies. Statistic: The<br />

mean length of the sample; x 5 4.8 cm.<br />

(b) No; in the 200 simulated<br />

samples, 21 of the SRSs had a mean<br />

of 4.8 or less. Based on the simulation,<br />

P( x ≤ 4.8) = 21∙200 = 0.105.<br />

(c) No; because the probability from<br />

part (b) isn’t small, it is plausible that the<br />

true mean is m 5 5 and I got a sample<br />

mean of x 5 4.8 by chance alone.<br />

15. (a) The distribution of heights for<br />

16-year-old females is approximately<br />

normal with a mean of m 5 64 inches<br />

and standard deviation of s 5 2.5 inches.<br />

56.5 59 61.5 64 66.5<br />

Height (in.)<br />

69 71.5<br />

(b) Answers will vary. This is the distribution<br />

of one possible sample.<br />

d d<br />

d ddd<br />

d d ddd ddddddd d d<br />

55 60 65 70<br />

Height (in.)<br />

16. (a) The distribution of measured<br />

weights for all scales is approximately<br />

normal with a mean of m 5 150 pounds<br />

and standard deviation of s 5 2 pounds.<br />

144 146 148 150 152<br />

Weight (lb)<br />

154 156<br />

(b) Answers will vary. This is the<br />

distribution of one possible sample.<br />

d d d d d dd dd d d d<br />

146 147 148 149 150 151 152 153 154 155<br />

Weight (lb)<br />

17. (a) In 10 cases of taking a random<br />

sample of size n 5 50 from each high<br />

school, the difference in proportions of<br />

students with Internet access at home<br />

is 0%. This means the proportion of<br />

students with Internet access was the<br />

same for each high school in 10 pairs of<br />

simulated samples<br />

(b) Yes; in the 100 pairs of simulated<br />

samples, 0 of the pairs had a<br />

difference in proportions of 0.20<br />

or higher. Based on the simulation,<br />

P(p^ N − p^ S ≥ 0.20) = 0∙100 = 0.<br />

(c) Yes; because the probability from<br />

part (b) is small, it is not plausible that<br />

the true difference in proportions is<br />

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d d d d d d d d d d d d d d d d d d d d d d d d d d d d ddd<br />

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4.6 4.8 5.0 5.2 5.4<br />

Sample mean length (cm)<br />

(b) Would it be unusual to get a sample mean of x = 4.8<br />

centimeters or less in a sample of size n 5 10 from<br />

this population? Explain.<br />

(c) Based on your answer to part (b), is there convincing<br />

evidence that the mean length of guppies at this<br />

store is less than 5 centimeters? Explain.<br />

15. More tall girls Refer to Exercise 11.<br />

(a) Make a graph of the population distribution of<br />

heights for 16-year-old females.<br />

(b) Sketch a possible dotplot of the distribution of sample<br />

data for an SRS of size 20 from this population.<br />

16. More bathroom scales Refer to Exercise 12.<br />

(a) Make a graph of the population distribution of<br />

weights, assuming the manufacturer’s claim is correct.<br />

(b) Sketch a possible dotplot of the distribution of sample<br />

data for an SRS of size 12 from this population.<br />

Extending the Concepts<br />

17. Difference of proportions A school superintendent<br />

believes that the proportion of North High School<br />

students with Internet access at home is greater<br />

than the proportion of South High School students<br />

with Internet access at home. To investigate, she<br />

selects SRSs of size n 5 50 from each school and<br />

finds p^ N 5 46/50 5 0.92 and p^ S 5 36/50 5 0.72.<br />

To determine if a difference in proportions of<br />

0.20 provides convincing evidence that North High<br />

School has a greater proportion of students with<br />

Internet access at home, we simulated two random<br />

samples of size n 5 50 from populations with the<br />

same proportion of students with Internet access.<br />

Then, we subtracted the sample proportions. Here<br />

are the results from repeating this process 100 times.<br />

d<br />

d<br />

d<br />

d<br />

d<br />

d<br />

d<br />

Starnes_<strong>3e</strong>_CH06_398-449_Final.indd 408<br />

p N 2 p S 5 0 and the superintendent<br />

got a sample difference of proportion of<br />

p^ N − p^ S = 0.20 by chance alone.<br />

18. (a) 300 C 25 = 1.95 × 10 36 different<br />

possible samples of 25 tomatoes.<br />

(b) Due to the extremely large number of<br />

possible samples, it is not practical to examine<br />

the complete sampling distribution of means<br />

for samples of size 25.<br />

19. (a) z = x − m<br />

s ;<br />

28,000 − 23,300<br />

0.67 = ;<br />

s<br />

s = 7014.93<br />

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–0.20 –0.10 0.00 0.10 0.20<br />

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with Internet access at home<br />

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(a) There are ten dots at 0. Explain what these dots<br />

represent.<br />

(b) Would it be unusual to get a difference in sample<br />

proportions of at least 0.20 when there is no difference<br />

in the population proportions? Explain.<br />

(c) Based on your answer to part (b), is there convincing<br />

evidence that North High School has a greater<br />

proportion of students with Internet access at<br />

home? Explain.<br />

Recycle and Review<br />

18. Sampling tomatoes (4.8, 6.1) Zach runs a roadside<br />

stand during the summer, selling produce from his<br />

farm. On a single day in mid-August, he harvests<br />

300 tomatoes. Suppose Zach wants to take a simple<br />

random sample of 25 tomatoes from the day’s<br />

pick to estimate mean weight.<br />

(a) How many possible sets of 25 tomatoes could<br />

be sampled from the 300 tomatoes in the day’s<br />

crop?<br />

(b) What does this say about the practicality of examining<br />

the complete sampling distribution of the sample<br />

mean for samples of size 25 from this population?<br />

19. College debt (5.7) A report published by the Federal<br />

Reserve Bank of New York in 2012 reported the<br />

results of a nationwide study of college student<br />

debt. Researchers found that the average student<br />

loan balance per borrower is $23,300. They also<br />

reported that about one-quarter of borrowers owe<br />

more than $28,000. 4<br />

(a) Assuming that the distribution of student loan<br />

balances is approximately normal, estimate the<br />

standard deviation of the distribution of student<br />

loan balances.<br />

(b) Assuming that the distribution of student loan<br />

balances is approximately normal, use your answer<br />

to part (a) to estimate the proportion of borrowers<br />

who owe more than $54,000.<br />

(c) In fact, the report states that about 10% of borrowers<br />

owe more than $54,000. What does this<br />

fact indicate about the shape of the distribution of<br />

student loan balances?<br />

(d) The report also states that the median student loan<br />

balance is $12,800. Does this fact support your<br />

conclusion in part (c)? Explain.<br />

54,000 − 23,300<br />

(b) z =<br />

≈ 4.38;<br />

7014.93<br />

P(X ≥ 54,000)≈ P(Z ≥ 4.38) ≈ 0<br />

Using technology: Applet/normalcdf(lower:<br />

54000, upper:100000, mean:23300,<br />

SD:7014.93) 5 0.000006<br />

(c) If the distribution of loan balances is<br />

approximately normal, then we would expect<br />

almost no one to have a balance that large.<br />

Because 10% of borrowers owe more than<br />

$54,000, we can conclude that the distribution<br />

of loan balances isn’t normal and is rightskewed.<br />

(d) Yes; because the mean ($23,300) is so<br />

much larger than the median ($12,800), we can<br />

conclude that the distribution of loan balances<br />

is skewed to the right.<br />

18/08/16 4:59 PMStarnes_<strong>3e</strong>_CH0<br />

408<br />

C H A P T E R 6 • Sampling Distributions<br />

Starnes_<strong>3e</strong>_ATE_CH06_398-449_v3.indd 408<br />

11/01/17 3:54 PM

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