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Concrete mathematics : a foundation for computer science

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5 EXERCISES 235<br />

47 The sum tk (rkk+s) (‘“;~~~“) is a polynomial in r and s. Show that it<br />

doesn’t depend on s.<br />

48 The identity xkGn (“Lk)2pk = 2n can be combined with tk30 (“lk)zk =<br />

l/(1 - 2) n+’ to yield tk>n (“~“)2~” = 2”. What is the hypergeometric<br />

<strong>for</strong>m of the latter identity?<br />

49 Use the hypergeometric method to evaluate<br />

50 Prove Pfaff’s reflection law (5.101) by comparing the coefficients of 2” on<br />

both sides of the equation.<br />

51 The derivation of (5.104) shows that<br />

lime+0 F(-m, -2m - 1 + e; -2m + e; 2) = l/ (-z2) .<br />

In this exercise we will see that slightly different limiting processes lead<br />

to distinctly different answers <strong>for</strong> the degenerate hypergeometric series<br />

F( -m, -2m - 1; -2m; 2).<br />

a Show that lime+~ F(-m + e, -2m - 1; -2m + 2e; 2) = 0, by using<br />

Pfaff’s reflection law to prove the identity F(a, -2m - 1; 2a; 2) = 0<br />

<strong>for</strong> all integers m 3 0.<br />

b What is lime+~ F(-m + E, -2m - 1; -2m + e; 2)?<br />

52 Prove that if N is a nonnegative integer,<br />

br].<br />

N<br />

= a, . . .<br />

l-bl-N,.. . , l-b,-N,-N<br />

1-al-N,...,l-am--N<br />

53 If we put b = -5 and z = 1 in Gauss’s identity (5.110), the left side<br />

reduces to -1 while the right side is fl. Why doesn’t this prove that<br />

-1 =+l?<br />

54 Explain how the right-hand side of (5.112) was obtained.<br />

55 If the hypergeometric terms t(k) = F(al , . . . , a,,,; bl, . . , , b,; z)k and<br />

T(k) = F(A,,... ,AM;B~,...,BN;Z)~ satisfy t(k) = c(T(k+ 1) -T(k))<br />

<strong>for</strong> all k 3 0, show that z = Z and m - n = M - N.<br />

56 Find a general <strong>for</strong>mula <strong>for</strong> t (i3) 6k using Gosper’s method. Show that<br />

(-l)k-’ [y] [y] is also a solution.

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