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Concrete mathematics : a foundation for computer science

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222 BINOMIAL COEFFICIENTS<br />

One use of this differential theory is to find and prove new trans<strong>for</strong>mations.<br />

For example, we can readily verify that both of the hypergeometrics<br />

satisfy the differential equation<br />

~(1 -z)F"(z) + (afb +- ;)(l -2z)F'(z) -4abF(z) = 0;<br />

hence Gauss’s identity [116, equation 1021<br />

(5.110)<br />

must be true. In particular, ICaution: We can’t<br />

use (5.110) safely<br />

when Izl > l/Z,<br />

F( ,:4;:; 1;) = F(o+4;IT-11’) ’<br />

2<br />

whenever both infinite sums converge.<br />

(5.111) unless both sides<br />

are polynomials;<br />

see exercise 53.)<br />

Every new identity <strong>for</strong> hypergeometrics has consequences <strong>for</strong> binomial<br />

coefficients, and this one is no exception. Let’s consider the sum<br />

&(m,k)(m+r+l) (q)“, integersm>n>O.<br />

The terms are nonzero <strong>for</strong> 0 < k < m - n, and with a little delicate limittaking<br />

as be<strong>for</strong>e we can express this sum as the hypergeometric<br />

n-m, -n-m-lfae<br />

liio m F<br />

0 n ( -m+ 6<br />

The value of OL doesn’t affect the limit, since the nonpositive upper parameter<br />

n - m cuts the sum off early. We can set OL = 2, so that (5.111) applies.<br />

The limit can now be evaluated because the right-hand side is a special case<br />

of (5.92). The result can be expressed in simplified <strong>for</strong>m,<br />

gm,k)(m+,+l) (G)<br />

= ((m+nn1’2)2nPm[m+n is even], ~~~~o, (5.112)<br />

as shown in exercise 54. For example, when m = 5 and n = 2 we get<br />

(z)(i) - ($($/2 + (:)(;)/4 -- (z)(i)/8 = 10 - 24 + 21 - 7 = 0; when m = 4<br />

and n = 2, both sides give z.

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