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55. (b) V ln 2<br />
A(x)dx ln 2<br />
(p/4) e 2x dx<br />
<br />
<br />
55. Each cross section of the solid infinite horn shown in the figure<br />
cut by a plane perpendicular to the x-axis for x ln 2 is a<br />
circular disc with one diameter reaching from the x-axis to the<br />
curve y e x .<br />
y<br />
2<br />
y = e x<br />
1<br />
0<br />
ln 2<br />
(a) Find the area of a typical cross section. A(x) (p/4) e 2x<br />
(b) Express the volume of the horn as an improper integral.<br />
(c) Find the volume of the horn. p/2<br />
56. Normal Probability Distribution Function In Section 7.5,<br />
we encountered the bell-shaped normal distribution curve that is<br />
the graph of<br />
1 ( ) 2<br />
f x 1 x m<br />
2 s<br />
,<br />
2<br />
the normal probability density function with mean m and<br />
standard deviation s. The number m tells where the distribution<br />
is centered, and s measures the “scatter” around the mean.<br />
From the theory of probability, it is known that<br />
<br />
f x dx 1.<br />
<br />
In what follows, let m 0 and s 1.<br />
(a) Draw the graph of f. Find the intervals on which f is<br />
increasing, the intervals on which f is decreasing, and any local<br />
extreme values and where they occur.<br />
(b) Evaluate<br />
n<br />
f x dx for n 1, 2, 3.<br />
n<br />
(c) Give a convincing argument that<br />
<br />
f x dx 1.<br />
<br />
(Hint: Show that 0 f x e x2 for x 1, and for b 1,<br />
<br />
e x2 dx→0 as b→.)<br />
b<br />
57. Approximating the Value of 1 e x2 dx<br />
(a) Show that<br />
<br />
6<br />
e x2 dx <br />
e 6x dx 4 10 17 .<br />
1 1<br />
31. 0 1 e x e x on [1, ), converges because 1<br />
<br />
1 e x dx converges<br />
34.<br />
1 1<br />
32. 0 x 3 <br />
1 x 3 on [1, ), converges because 1<br />
<br />
1 x 3 dx converges<br />
33. 0 1 x 2 cos x<br />
on [p, ), diverges because 1 dx diverges<br />
x<br />
p x<br />
6<br />
x<br />
Section 8.4 Improper Integrals 469<br />
(b) Writing to Learn Explain why<br />
<br />
1<br />
e x2 dx 6<br />
e x2 dx<br />
with error of at most 4 10 17 .<br />
(c) Use the approximation in part (b) to estimate the value of<br />
1 e x2 dx. Compare this estimate with the value displayed in<br />
Figure 8.19.<br />
(d) Writing to Learn Explain why<br />
<br />
0<br />
e x2 dx 3<br />
e x2 dx<br />
with error of at most 0.000042.<br />
Extending the Ideas<br />
58. Use properties of integrals to give a convincing argument that<br />
Theorem 6 is true.<br />
59. Consider the integral<br />
f n 1 <br />
x n e x dx<br />
0<br />
where n 0.<br />
(a) Show that 0<br />
x n e x dx converges for n 0, 1, 2.<br />
(b) Use integration by parts to show that f n 1 nfn.<br />
(c) Give a convincing argument that 0<br />
x n e x dx converges for<br />
all integers n 0.<br />
60. Let f x x<br />
sin t<br />
dt.<br />
0<br />
t<br />
(a) Use graphs and tables to investigate the values of f x<br />
as x→.<br />
(b) Does the integral 0<br />
sin xx dx converge? Give a<br />
convincing argument.<br />
61. (a) Show that we get the same value for the improper integral in<br />
Example 5 if we express<br />
<br />
1 <br />
<br />
dxx 1<br />
2 <br />
1 <br />
dxx 2<br />
1<br />
0<br />
<br />
and then evaluate these two integrals.<br />
1<br />
,<br />
1 <br />
dxx 2<br />
(b) Show that it doesn’t matter what we choose for c in<br />
(Improper Integrals with Infinite Integration Limits, part 3)<br />
<br />
f x dx c<br />
<br />
<br />
f x dx <br />
f x dx.<br />
<br />
dx<br />
<br />
x 4<br />
2<br />
1<br />
dx<br />
0<br />
x 4<br />
21<br />
1<br />
dx<br />
0<br />
x 4<br />
2<br />
1<br />
dx<br />
1<br />
x and<br />
4<br />
1<br />
1<br />
0 <br />
x 4<br />
1<br />
1<br />
x2 on [1, ), converges because 1<br />
<br />
1 x 2 dx converges<br />
c