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448 Chapter 8 Sequences, L’Hôpital’s Rule, and Improper Integrals<br />

) .<br />

EXAMPLE 7<br />

Find lim<br />

x→1 ( 1 1<br />

<br />

ln x x 1<br />

Working with Indeterminate Form <br />

SOLUTION<br />

Combining the two fractions converts the indeterminate form to 00, to which<br />

we can apply l’Hôpital’s Rule.<br />

lim<br />

x→1 ( 1 1<br />

<br />

ln x x <br />

) 1<br />

lim x 1 ln<br />

x<br />

Now 0 x→1 x 1 ln<br />

x<br />

0 <br />

1 1x<br />

lim<br />

x→1<br />

x 1<br />

ln x<br />

x<br />

x 1<br />

lim Still 0 x→1 x ln x x 1 0 <br />

lim <br />

x→1 2 <br />

1ln x<br />

1 2 Now try Exercise 19.<br />

Indeterminate Forms 1 , 0 0 , 0<br />

Limits that lead to the indeterminate forms 1 ,0 0 , and 0 can sometimes be handled by<br />

taking logarithms first. We use l’Hôpital’s Rule to find the limit of the logarithm and then<br />

exponentiate to reveal the original function’s behavior.<br />

Since b e ln b for every positive number<br />

b, we can write fx as<br />

fx eln fx<br />

for any positive function fx.<br />

lim ln f x L ⇒ lim f x lim e ln f x e L<br />

x→a x→a x→a<br />

Here a can be finite or infinite.<br />

In Section 1.3 we used graphs and tables to investigate the values of f x 1 1x x<br />

as x→. Now we find this limit with l’Hôpital’s Rule.<br />

EXAMPLE 8<br />

Find<br />

lim<br />

x→ (<br />

Working with Indeterminate Form 1 <br />

x<br />

1 1 x ) .<br />

SOLUTION<br />

Let f x 1 1x x . Then taking logarithms of both sides converts the indeterminate<br />

form 1 to 00, to which we can apply l’Hôpital’s Rule.<br />

x ln<br />

ln f x ln ( 1 1 x ) x ln ( 1 1 x )<br />

( 1 1<br />

x ) <br />

<br />

1 x <br />

continued

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