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448 Chapter 8 Sequences, L’Hôpital’s Rule, and Improper Integrals<br />
) .<br />
EXAMPLE 7<br />
Find lim<br />
x→1 ( 1 1<br />
<br />
ln x x 1<br />
Working with Indeterminate Form <br />
SOLUTION<br />
Combining the two fractions converts the indeterminate form to 00, to which<br />
we can apply l’Hôpital’s Rule.<br />
lim<br />
x→1 ( 1 1<br />
<br />
ln x x <br />
) 1<br />
lim x 1 ln<br />
x<br />
Now 0 x→1 x 1 ln<br />
x<br />
0 <br />
1 1x<br />
lim<br />
x→1<br />
x 1<br />
ln x<br />
x<br />
x 1<br />
lim Still 0 x→1 x ln x x 1 0 <br />
lim <br />
x→1 2 <br />
1ln x<br />
1 2 Now try Exercise 19.<br />
Indeterminate Forms 1 , 0 0 , 0<br />
Limits that lead to the indeterminate forms 1 ,0 0 , and 0 can sometimes be handled by<br />
taking logarithms first. We use l’Hôpital’s Rule to find the limit of the logarithm and then<br />
exponentiate to reveal the original function’s behavior.<br />
Since b e ln b for every positive number<br />
b, we can write fx as<br />
fx eln fx<br />
for any positive function fx.<br />
lim ln f x L ⇒ lim f x lim e ln f x e L<br />
x→a x→a x→a<br />
Here a can be finite or infinite.<br />
In Section 1.3 we used graphs and tables to investigate the values of f x 1 1x x<br />
as x→. Now we find this limit with l’Hôpital’s Rule.<br />
EXAMPLE 8<br />
Find<br />
lim<br />
x→ (<br />
Working with Indeterminate Form 1 <br />
x<br />
1 1 x ) .<br />
SOLUTION<br />
Let f x 1 1x x . Then taking logarithms of both sides converts the indeterminate<br />
form 1 to 00, to which we can apply l’Hôpital’s Rule.<br />
x ln<br />
ln f x ln ( 1 1 x ) x ln ( 1 1 x )<br />
( 1 1<br />
x ) <br />
<br />
1 x <br />
continued