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5128_Ch07_pp378-433

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Section 7.3 Volumes 403<br />

2. Identify the limits of integration: y runs from 0 to 2.<br />

3. Integrate to find the volume.<br />

V 2<br />

0<br />

2<br />

0<br />

2p( radius)( shell<br />

height) shell dy<br />

2py4 y 2 dy 8p<br />

Now try Exercise 33(a).<br />

4<br />

2<br />

y<br />

0 2<br />

Figure 7.28 The region and the height<br />

of a typical shell in Example 5.<br />

o<br />

x k<br />

[–1, 3.5] by [–0.8, 2.2]<br />

Figure 7.29 The base of the paperweight<br />

in Example 6. The segment perpendicular<br />

to the x-axis at x k is the diameter of<br />

a semicircle that is perpendicular to the<br />

base.<br />

0<br />

2<br />

y<br />

x<br />

x<br />

π<br />

y = 2 sin x<br />

Figure 7.30 Cross sections perpendicular<br />

to the region in Figure 7.29 are semicircular.<br />

(Example 6)<br />

<br />

EXAMPLE 5<br />

Finding Volumes Using Cylindrical Shells<br />

The region bounded by the curves y 4 x 2 , y x, and x 0 is revolved about the<br />

y-axis to form a solid. Use cylindrical shells to find the volume of the solid.<br />

SOLUTION<br />

1. Sketch the region and draw a line segment across it parallel to the y-axis<br />

(Figure 7.28). The segment’s length (shell height) is 4 x 2 x. The distance of the<br />

segment from the axis of revolution (shell radius) is x.<br />

2. Identify the limits of integration: The x-coordinate of the point of intersection of the<br />

curves y 4 x 2 and y x in the first quadrant is about 1.562. So x runs from 0 to<br />

1.562.<br />

3. Integrate to find the volume.<br />

Other Cross Sections<br />

radius)( height) shell dx<br />

1.562<br />

2p(x)(4 x 2 x) dx<br />

0<br />

13.327<br />

1.562<br />

V 2p ( shell<br />

0<br />

Now try Exercise 35.<br />

The method of cross-section slicing can be used to find volumes of a wide variety of unusually<br />

shaped solids, so long as the cross sections have areas that we can describe with<br />

some formula. Admittedly, it does take a special artistic talent to draw some of these<br />

solids, but a crude picture is usually enough to suggest how to set up the integral.<br />

EXAMPLE 6<br />

A Mathematician’s Paperweight<br />

A mathematician has a paperweight made so that its base is the shape of the region between<br />

the x-axis and one arch of the curve y 2 sin x (linear units in inches). Each cross<br />

section cut perpendicular to the x-axis (and hence to the xy-plane) is a semicircle whose<br />

diameter runs from the x-axis to the curve. (Think of the cross section as a semicircular<br />

fin sticking up out of the plane.) Find the volume of the paperweight.<br />

SOLUTION<br />

The paperweight is not easily drawn, but we know what it looks like. Its base is the region<br />

in Figure 7.29, and the cross sections perpendicular to the base are semicircular fins like<br />

those in Figure 7.30.<br />

The semicircle at each point x has<br />

radius 2s in x<br />

sin x and area Ax 1 2<br />

2 psin x2 .<br />

continued

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