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5128_Ch07_pp378-433

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398 Chapter 7 Applications of Definite Integrals<br />

Exploration<br />

56. Group Activity Area of Ellipse<br />

An ellipse with major axis of length 2a and minor axis of<br />

length 2b can be coordinatized with its center at the origin and<br />

its major axis horizontal, in which case it is defined by the<br />

equation<br />

Extending the Ideas<br />

57. Cavalieri’s Theorem Bonaventura Cavalieri (1598–1647)<br />

discovered that if two plane regions can be arranged to lie over<br />

the same interval of the x-axis in such a way that they have<br />

identical vertical cross sections at every point (see figure), then<br />

the regions have the same area. Show that this theorem is true.<br />

x<br />

2 a<br />

2 y 2 b<br />

2 1.<br />

(a) Find the equations that define the upper and lower<br />

semiellipses as functions of x.<br />

(b) Write an integral expression that gives the area of the ellipse.<br />

(c) With your group, use NINT to find the areas of ellipses for<br />

various lengths of a and b.<br />

(d) There is a simple formula for the area of an ellipse with<br />

major axis of length 2a and minor axis of length 2b. Can you<br />

tell what it is from the areas you and your group have found?<br />

(e) Work with your group to write a proof of this area formula<br />

by showing that it is the exact value of the integral expression<br />

in part (b).<br />

<br />

56. (a) y b <br />

1 a<br />

x 2 2 <br />

(b) 2 a b<br />

a <br />

x<br />

1 <br />

2 a<br />

2 dx<br />

(c) Answers may vary.<br />

(d, e) abp<br />

a x b<br />

Cross sections have<br />

the same length at<br />

every point in [a, b].<br />

58. Find the area of the region enclosed by the curves<br />

x<br />

y x 2 and<br />

1<br />

y mx, 0 m 1.<br />

m ln (m) 1<br />

57. Since f (x) g(x) is the same for each region where f (x) and g(x) represent<br />

the upper and lower edges, area b [ f (x) g(x)] dx will be the same for<br />

a<br />

each.

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