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5128_Ch03_pp098-184

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174 Chapter 3 Derivatives<br />

EXPLORATION 1<br />

Leaving Milk on the Counter<br />

A glass of cold milk from the refrigerator is left on the counter on a warm summer<br />

day. Its temperature y (in degrees Fahrenheit) after sitting on the counter t minutes is<br />

y 72 300.98 t .<br />

Answer the following questions by interpreting y and dydt.<br />

1. What is the temperature of the refrigerator? How can you tell?<br />

2. What is the temperature of the room? How can you tell?<br />

3. When is the milk warming up the fastest? How can you tell?<br />

4. Determine algebraically when the temperature of the milk reaches 55°F.<br />

5. At what rate is the milk warming when its temperature is 55°F? Answer with<br />

an appropriate unit of measure.<br />

This equation answers what was once a<br />

perplexing problem: Is there a function<br />

with derivative x 1 ? All of the other<br />

power functions follow the Power Rule,<br />

d<br />

x n nx n1 .<br />

d x<br />

However, this formula is not much help<br />

if one is looking for a function with x 1<br />

as its derivative! Now we know why: The<br />

function we should be looking for is not<br />

a power function at all; it is the natural<br />

logarithm function.<br />

Derivative of ln x<br />

Now that we know the derivative of e x , it is relatively easy to find the derivative of its inverse<br />

function, ln x.<br />

y ln x<br />

e y x Inverse function relationship<br />

d<br />

e d x<br />

y d<br />

x<br />

d x<br />

e y dy<br />

1 d x<br />

dy 1<br />

d x e y 1 x <br />

If u is a differentiable function of x and u 0,<br />

Differentiate implicitly.<br />

d<br />

ln u 1 d x u d u<br />

.<br />

dx<br />

2<br />

1<br />

0<br />

y<br />

(a, ln a)<br />

slope = 1 a<br />

–<br />

1 2 3 4 5<br />

y = ln x<br />

Figure 3.57 The tangent line intersects<br />

the curve at some point a, lna, where the<br />

slope of the curve is 1a. (Example 3)<br />

x<br />

EXAMPLE 3 A Tangent through the Origin<br />

A line with slope m passes through the origin and is tangent to the graph of y ln x.<br />

What is the value of m?<br />

SOLUTION<br />

This problem is a little harder than it looks, since we do not know the point of tangency.<br />

However, we do know two important facts about that point:<br />

1. it has coordinates a, lna for some positive a, and<br />

2. the tangent line there has slope m 1a (Figure 3.57).<br />

Since the tangent line passes through the origin, its slope is<br />

m ln a <br />

a <br />

0<br />

0<br />

ln a<br />

a .<br />

continued

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