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5128_Ch03_pp098-184

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Section 3.4 Velocity and Other Rates of Change 137<br />

18. Launching a Rocket When a model rocket is launched,<br />

the propellant burns for a few seconds, accelerating the rocket<br />

upward. After burnout, the rocket coasts upward for a while<br />

and then begins to fall. A small explosive charge pops out a<br />

parachute shortly after the rocket starts downward. The<br />

parachute slows the rocket to keep it from breaking when it<br />

lands. This graph shows velocity data from the flight.<br />

Velocity (ft/sec)<br />

200<br />

150<br />

100<br />

50<br />

0<br />

–50<br />

–100<br />

0 2 4 6 8 10 12<br />

Time after launch (sec)<br />

Use the graph to answer the following.<br />

190 ft/sec<br />

(a) How fast was the rocket climbing when the engine stopped?<br />

(b) For how many seconds did the engine burn? 2 seconds<br />

(c) When did the rocket reach its highest point? What was its<br />

velocity then? After 8 seconds, and its velocity was 0 ft/sec then<br />

(d) When did the parachute pop out? How fast was the rocket<br />

falling then? After about 11 seconds; it was falling 90 ft/sec then.<br />

(e) How long did the rocket fall before the parachute opened?<br />

About 3 seconds<br />

(f) When was the rocket’s acceleration greatest? When was the<br />

acceleration constant? Just before the engine stopped; from t = 2<br />

to t = 11 while the rocket was in free fall<br />

19. Particle Motion A particle moves along a line so that its<br />

position at any time t 0 is given by the function<br />

st t 2 3t 2,<br />

where s is measured in meters and t is measured in seconds.<br />

(a) Find the displacement during the first 5 seconds. 10 m<br />

(b) Find the average velocity during the first 5 seconds. 2 m/sec<br />

(c) Find the instantaneous velocity when t 4.<br />

5 m/sec<br />

(d) Find the acceleration of the particle when t 4. 2 m/sec 2<br />

(e) At what values of t does the particle change direction?<br />

(f) Where is the particle when s is a minimum? At s 1 4 m<br />

20. Particle Motion A particle moves along a line so that its<br />

position at any time t 0 is given by the function s(t) <br />

t 3 7t 2 14t 8 where s is measured in meters and t is<br />

measured in seconds.<br />

v(t) 3t 2 14t 14<br />

(a) Find the instantaneous velocity at any time t.<br />

a(t) 6t 14<br />

(b) Find the acceleration of the particle at any time t.<br />

(c) When is the particle at rest? t 1.451, 3.215<br />

(d) Describe the motion of the particle. At what values of t does<br />

the particle change directions?<br />

21. Particle Motion A particle moves along a line so that its<br />

position at any time t 0 is given by the function s (t) <br />

(t 2) 2 (t 4) where s is measured in meters and t is measured<br />

in seconds.<br />

v(t) 3t 2 16t 20 (t 2)(3t 10)<br />

(a) Find the instantaneous velocity at any time t.<br />

(b) Find the acceleration of the particle at any time t. a(t) 6t 16<br />

(c) When is the particle at rest? t 2, 10/3<br />

(d) Describe the motion of the particle. At what values of t does<br />

the particle change directions?<br />

22. Particle Motion A particle moves along a line so that its<br />

position at any time t 0 is given by the function s (t) <br />

t 3 6t 2 8t 2 where s is measured in meters and t is<br />

measured in seconds.<br />

v(t) 3t 2 12t 8<br />

(a) Find the instantaneous velocity at any time t.<br />

(b) Find the acceleration of the particle at any time t. a(t) 6t 12<br />

(c) When is the particle at rest? t 0.845, 3.155<br />

(d) Describe the motion of the particle. At what values of t does<br />

the particle change directions?<br />

23. Particle Motion The position of a body at time t sec is<br />

s t 3 6t 2 9t m. Find the body’s acceleration each<br />

time the velocity is zero. At t 1; 6 m/sec 2 At t 3: 6 m/sec 2<br />

24. Finding Speed A body’s velocity at time t sec is<br />

v 2t 3 9t 2 12t 5 msec. Find the body’s speed<br />

each time the acceleration is zero. At t 1: 0 m/sec; at t 2:1 m/sec<br />

25. Draining a Tank It takes 12 hours to drain a storage tank by<br />

opening the valve at the bottom. The depth y of fluid in the tank<br />

t hours after the valve is opened is given by the formula<br />

2<br />

y 6( 1 t<br />

12<br />

) m.<br />

(a) Find the rate dydt mh at which the water level is<br />

changing at time t. d y t<br />

1<br />

dt<br />

1 2<br />

(b) When is the fluid level in the tank falling fastest? slowest?<br />

What are the values of dydt at these times?<br />

At t 3 2 sec<br />

(c) Graph y and dydt together and discuss the behavior of y<br />

in relation to the signs and values of dydt.<br />

20. (d) The particle starts at the point s 8 and moves left until it stops at<br />

s 0.631 at t 1.451, then it moves right to the point s 2.213 at t <br />

3.215,) where it stops again, and finally continues left from there on.<br />

21. (d) The particle starts at the point s 16 when t 0 and moves right<br />

until it stops at s 0 when t 2, then it moves left to the point s 1.185<br />

when t 10/3 where it stops again, and finally continues right from there on.<br />

22. (d) The particle starts at the point s 2 when t 0 and moves right until<br />

it stops at s 5.079 at t 0.845, then it moves left to the point s 1.079 at<br />

t 3.155 where it stops again, and finally continues right from there on.<br />

25. (b) Fastest: at t 0 slowest: at t 12; at t 0: d y<br />

1;<br />

dt<br />

at t = 12: d y<br />

0<br />

dt

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