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5128_Ch03_pp098-184

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134 Chapter 3 Derivatives<br />

0<br />

y (dollars)<br />

Slope <br />

marginal cost<br />

x<br />

(tons/week)<br />

x h<br />

y c(x)<br />

x<br />

In a manufacturing operation, the cost of production cx is a function of x, the number<br />

of units produced. The marginal cost of production is the rate of change of cost with respect<br />

to the level of production, so it is dcdx.<br />

Suppose cx represents the dollars needed to produce x tons of steel in one week. It<br />

costs more to produce x h tons per week, and the cost difference divided by h is the<br />

average cost of producing each additional ton.<br />

cx h cx<br />

h<br />

<br />

{<br />

the average cost of each of the<br />

additional h tons produced<br />

Figure 3.30 Weekly steel production:<br />

cx is the cost of producing x tons per<br />

week. The cost of producing an additional<br />

h tons per week is cx h cx.<br />

y<br />

x 1<br />

⎧<br />

⎪<br />

⎨<br />

⎪<br />

⎩<br />

c<br />

y c(x)<br />

dc—<br />

dx<br />

The limit of this ratio as h→0 is the marginal cost of producing more steel per week<br />

when the current production is x tons (Figure 3.30).<br />

d c<br />

lim cx h cx<br />

marginal cost of production<br />

dx<br />

h→0 h<br />

Sometimes the marginal cost of production is loosely defined to be the extra cost of producing<br />

one more unit,<br />

c<br />

cx 1 cx<br />

,<br />

x 1<br />

which is approximated by the value of dcdx at x. This approximation is acceptable if the<br />

slope of c does not change quickly near x, for then the difference quotient is close to its limit<br />

dcdx even if x 1 (Figure 3.31). The approximation works best for large values of x.<br />

0 x<br />

x + 1<br />

Figure 3.31 Because dcdx is the slope<br />

of the tangent at x, the marginal cost dcdx<br />

approximates the extra cost c of producing<br />

x 1 more unit.<br />

x<br />

EXAMPLE 7 Marginal Cost and Marginal Revenue<br />

Suppose it costs<br />

cx x 3 6x 2 15x<br />

dollars to produce x radiators when 8 to 10 radiators are produced, and that<br />

rx x 3 3x 2 12x<br />

gives the dollar revenue from selling x radiators. Your shop currently produces<br />

10 radiators a day. Find the marginal cost and marginal revenue.<br />

SOLUTION<br />

The marginal cost of producing one more radiator a day when 10 are being produced<br />

is c10.<br />

d<br />

cx x d x<br />

3 6x 2 15x 3x 2 12x 15<br />

The marginal revenue is<br />

so,<br />

c10 3100 1210 15 195 dollars<br />

d<br />

rx x d x<br />

3 3x 2 12x 3x 2 6x 12,<br />

r10 3100 610 12 252 dollars.<br />

Now try Exercises 27 and 28.

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