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5128_Ch03_pp098-184

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132 Chapter 3 Derivatives<br />

–1<br />

6<br />

4<br />

2<br />

–2<br />

–4<br />

s(t)<br />

2 4 6<br />

Figure 3.27 The graphs of<br />

s(t) t 2 4t 3, t 0 (blue) and its<br />

derivative v(t) 2t 4, t 0 (red).<br />

(Example 5)<br />

X 1T =T2-4T+3 Y 1T =2<br />

t<br />

SOLUTION<br />

(a) The displacement is given by s(2) s(0) (1) 3 4. This value means that<br />

the particle is 4 units left of where it started.<br />

(b) The average velocity we seek is<br />

s(4 ) s(0)<br />

3 <br />

3<br />

0 m/sec.<br />

4 0 4<br />

(c) The velocity v(t) at any time t is v(t) ds/dt 2t 4. So v(4) 4 m/sec<br />

(d) The acceleration a(t) at any time t is a(t) dv/dt 2 m /sec 2 . So a(4) 2.<br />

(e) The graphs of s(t) t 2 4t 3 for t 0 and its derivative v(t) 2t 4 shown in<br />

Figure 3.27 will help us analyze the motion.<br />

For 0 t 2, v(t) 0, so the particle is moving to the left. Notice that s(t) is decreasing.<br />

The particle starts (t 0) at s 3 and moves left, arriving at the origin<br />

t 1 when s 0. The particle continues moving to the left until it reaches the point<br />

s 1 at t 2.<br />

At t 2, v 0, so the particle is at rest.<br />

For t 2, v(t) 0, so the particle is moving to the right. Notice that s(t) is increasing.<br />

In this interval, the particle starts at s 1, moving to the right through the origin<br />

and continuing to the right for the rest of time.<br />

The particle changes direction at t 2 when v 0.<br />

(f) Enter X 1T T 2 4T3, Y 1T 2 in parametric mode and graph in the window<br />

[5, 5 ] by [2, 4 ] with Tmin 0, Tmax 10 (it really should be ), and<br />

XsclYscl1. (Figure 3.28) By using TRACE you can follow the path of the particle.<br />

You will learn more ways to visualize motion in Explorations 2 and 3.<br />

Now try Exercise 19.<br />

T=0<br />

X=3<br />

Y=2<br />

[5, 5] by [2, 4]<br />

Figure 3.28 The graph of X 1T <br />

T 2 4T 3, Y 1T 2 in parametric<br />

mode. (Example 5)<br />

EXPLORATION 2<br />

Modeling Horizontal Motion<br />

The position (x-coordinate) of a particle moving on the horizontal line y 2 is<br />

given by xt 4t 3 16t 2 15t for t 0.<br />

1. Graph the parametric equations x 1 t 4t 3 16t 2 15t, y 1 t 2 in 4, 6<br />

by 3, 5. Use TRACE to support that the particle starts at the point 0, 2,<br />

moves to the right, then to the left, and finally to the right. At what times does<br />

the particle reverse direction?<br />

2. Graph the parametric equations x 2 t x 1 t, y 2 t t in the same viewing<br />

window. Explain how this graph shows the back and forth motion of the particle.<br />

Use this graph to find when the particle reverses direction.<br />

3. Graph the parametric equations x 3 t t, y 3 t x 1 t in the same viewing<br />

window. Explain how this graph shows the back and forth motion of the particle.<br />

Use this graph to find when the particle reverses direction.<br />

4. Use the methods in parts 1, 2, and 3 to represent and describe the velocity of the<br />

particle.

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