5128_Ch03_pp098-184
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Section 3.2 Differentiability 111<br />
y<br />
m 1 =<br />
f(a + h) – f(a – h)<br />
2h<br />
m 2 =<br />
f(a + h) – f(a)<br />
h<br />
tangent line<br />
Derivatives on a Calculator<br />
Many graphing utilities can approximate derivatives numerically with good accuracy at<br />
most points of their domains.<br />
For small values of h, the difference quotient<br />
f a h f a<br />
<br />
h<br />
a – h a a + h<br />
Figure 3.16 The symmetric difference<br />
quotient (slope m 1 ) usually gives a better<br />
approximation of the derivative for a given<br />
value of h than does the regular difference<br />
quotient (slope m 2 ), which is why the<br />
symmetric difference quotient is used in<br />
the numerical derivative.<br />
x<br />
is often a good numerical approximation of f a. However, as suggested by Figure 3.16,<br />
the same value of h will usually yield a better approximation if we use the symmetric<br />
difference quotient<br />
f a h f a h<br />
2h ,<br />
which is what our graphing calculator uses to calculate NDER f a, the numerical<br />
derivative of f at a point a. The numerical derivative of f as a function is denoted by<br />
NDER f x. Sometimes we will use NDER f x, a for NDER f a when we want to<br />
emphasize both the function and the point.<br />
Although the symmetric difference quotient is not the quotient used in the definition of<br />
f a, it can be proven that<br />
lim<br />
h→0<br />
f a h f a h<br />
2h<br />
equals f a wherever f a exists.<br />
You might think that an extremely small value of h would be required to give an accurate<br />
approximation of f a, but in most cases h 0.001 is more than adequate. In fact,<br />
your calculator probably assumes such a value for h unless you choose to specify otherwise<br />
(consult your Owner’s Manual). The numerical derivatives we compute in this book<br />
will use h 0.001; that is,<br />
f a 0.001 f a 0.001<br />
NDER f a <br />
<br />
0.002 .<br />
EXAMPLE 2<br />
Computing a Numerical Derivative<br />
Compute NDER x 3 ,2, the numerical derivative of x 3 at x 2.<br />
SOLUTION<br />
Using h 0.001,<br />
NDER x 3 ,2 <br />
2.001 3 1.999 3<br />
<br />
0.002<br />
12.000001.<br />
Now try Exercise 17.<br />
In Example 1 of Section 3.1, we found the derivative of x 3 to be 3x 2 , whose value<br />
at x 2 is 32 2 12. The numerical derivative is accurate to 5 decimal places. Not bad<br />
for the push of a button.<br />
Example 2 gives dramatic evidence that NDER is very accurate when h 0.001. Such<br />
accuracy is usually the case, although it is also possible for NDER to produce some surprisingly<br />
inaccurate results, as in Example 3.<br />
EXAMPLE 3<br />
Fooling the Symmetric Difference Quotient<br />
Compute NDER x, 0, the numerical derivative of x at x 0.<br />
continued