Textbook Chapter 1
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36 <strong>Chapter</strong> 1 Prerequisites for Calculus<br />
(b) Writing to Learn Let h 0 and k 2, 1, 1, and 2, in<br />
turn. Graph using the parameter interval [0, 2p]. Describe the<br />
role of k. k determines the y-coordinate of the center of the circle. It<br />
causes a vertical shift of the graph.<br />
(c) Find a parametrization for the circle with radius 5 and center<br />
at (2, 3). x 5 cos t 2, y 5 sin t 3, 0 t 2p<br />
(d) Find a parametrization for the ellipse centered at (3, 4)<br />
with semimajor axis of length 5 parallel to the x-axis and semiminor<br />
axis of length 2 parallel to the y-axis.x 5 cos t 3,<br />
y 2 sin t 4, 0 t 2p<br />
In Exercises 45 and 46, a parametrization is given for a curve.<br />
(a) Graph the curve. What are the initial and terminal points, if<br />
any? Indicate the direction in which the curve is traced.<br />
(b) Find a Cartesian equation for a curve that contains the parametrized<br />
curve. What portion of the graph of the Cartesian<br />
equation is traced by the parametrized curve?<br />
45. x sec t, y tan t, p2 t p2<br />
(b) x 2 – y 2 1; left branch (or x y ; 2 1 all)<br />
46. x tan t, y 2 sec t, p2 t p2<br />
(b) 2<br />
y <br />
2<br />
x 2 1; lower branch (or y 2x 2 1<br />
Extending the Ideas<br />
; all)<br />
47. The Witch of Agnesi The bell-shaped witch of Agnesi can be<br />
constructed as follows. Start with the circle of radius 1, centered<br />
at the point (0, 1) as shown in the figure.<br />
23. Possible answer: x 1 5t, y 3 4t, 0 t 1<br />
24. Possible answer: x 1 4t, y 3 5t, 0 t 1<br />
25. Possible answer: x t 2 1, y t, t 0<br />
26. Possible answer: x t, y t 2 2t, t 1<br />
35. Possible answers:<br />
(a) x a cos t, y a sin t, 0 t 2p<br />
(b) x a cos t, y a sin t, 0 t 2p<br />
(c) x a cos t, y a sin t, 0 t 4p<br />
(d) x a cos t, y a sin t, 0 t 4p<br />
36. Possible answers:<br />
(a) x a cos t, y b sin t, 0 t 2p<br />
(b) x a cos t, y b sin t, 0 t 2<br />
(c) x a cos t, y b sin t, 0 t 4<br />
(d) x a cos t, y b sin t, 0 t 4p<br />
y = 2<br />
Q<br />
(0, 1)<br />
O<br />
Choose a point A on the line y 2, and connect it to the origin<br />
with a line segment. Call the point where the segment crosses the<br />
circle B. Let P be the point where the vertical line through A<br />
crosses the horizontal line through B. The witch is the curve<br />
traced by P as A moves along the line y 2.<br />
Find a parametrization for the witch by expressing the coordinates<br />
of P in terms of t, the radian measure of the angle that segment<br />
OA makes with the positive x-axis. The following equalities<br />
(which you may assume) will help:<br />
(i) x AQ (ii) y 2 AB sin t (iii) AB # AO (AQ) 2<br />
x 2 cot t, y 2 sin 2 t ,0 t p<br />
48. Parametrizing Lines and Segments<br />
(a) Show that x x 1 (x 2 x 1 )t, y y 1 (y 2 y 1 )t,<br />
t is a parametrization for the line through<br />
the points (x 1 , y 1 ) and (x 2 , y 2 ).<br />
(b) Find a parametrization for the line segment with endpoints<br />
(x 1 , y 1 ) and (x 2 , y 2 ).<br />
48. (a) If x 2 x 1 then the line is a vertical line and the first parametric equation<br />
gives x x 1 , while the second will give all real values for y since<br />
it cannot be the case that y 2 y 1 as well. Otherwise, solving the first<br />
equation for t gives<br />
x<br />
x<br />
t <br />
1<br />
<br />
x 2 x1<br />
Substituting that into the second equation for t gives<br />
y<br />
y y 1 y 1<br />
<br />
x2<br />
2 x1<br />
<br />
(x x 1 )<br />
which is the point-slope form of the equation for the line through<br />
(x 1 , y 1 ) and (x 2 , y 2 ). Note that the first equation will cause x to take on<br />
all real values, because x 2 – x 1 is not zero. Therefore, all of the points<br />
on the line will be traced out.<br />
(b) Use the equations for x and y given in part (a) with 0 t 1.<br />
y<br />
B<br />
t<br />
A<br />
P(x, y)<br />
x