Textbook Chapter 1
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Section 1.3 Exponential Functions 27<br />
In Exercises 21–32, use an exponential model to solve the problem. 33. y 2x 3<br />
21. Population Growth The population of Knoxville is 500,000<br />
x y y<br />
x y Change ( ¢y)<br />
and is increasing at the rate of 3.75% each year. Approximately<br />
1 1<br />
2<br />
1 ?<br />
when will the population reach 1 million? After 19 years<br />
2 1<br />
?<br />
2<br />
3 3<br />
2 ?<br />
2<br />
22. Population Growth The population of Silver Run in the year<br />
? 4 5<br />
1890 was 6250. Assume the population increased at a rate of<br />
3 ?<br />
?<br />
2.75% per year.<br />
4 ?<br />
2 48 2.815 10 14<br />
(a) Estimate the population in 1915 and 1940.<br />
1915: 12,315;<br />
1940: 24,265<br />
(b) Approximately when did the population reach 50,000?<br />
1967 [76.651 years after 1890] 34. y 3x 4<br />
23. Radioactive Decay The half-life of phosphorus-32 is about<br />
x y Change ( ¢y)<br />
x y y<br />
14 days. There are 6.6 grams present initially.<br />
1 1<br />
1 ?<br />
3<br />
(a) Express the amount of phosphorus-32 remaining as a<br />
2 2<br />
?<br />
function of time t.<br />
A(t) 6.6<br />
1 2 ?<br />
2 t/14<br />
3<br />
3 5<br />
3<br />
?<br />
4 8<br />
(b) When will there be 1 gram remaining? About 38.1145 days later<br />
3 ?<br />
?<br />
24. Finding Time If John invests $2300 in a savings account with<br />
4 ?<br />
a 6% interest rate compounded annually, how long will it take<br />
until John’s account has a balance of $4150? 10.129 years<br />
35. y x 2<br />
25. Doubling Your Money Determine how much time is required<br />
x y y<br />
x y Change ( ¢y)<br />
for an investment to double in value if interest is earned at the<br />
1 1<br />
3<br />
rate of 6.25% compounded annually. 11.433 years<br />
1 ?<br />
2 4<br />
5<br />
?<br />
3 9<br />
26. Doubling Your Money Determine how much time is required<br />
2 ?<br />
7<br />
for an investment to double in value if interest is earned at the<br />
?<br />
4 16<br />
3 ?<br />
rate of 6.25% compounded monthly. 11.119 years<br />
?<br />
4 ?<br />
27. Doubling Your Money Determine how much time is required<br />
for an investment to double in value if interest is earned at the<br />
rate of 6.25% compounded continuously. 11.090 years<br />
36. y 3e x<br />
x y y<br />
28. Tripling Your Money Determine how much time is required<br />
x y Ratio (y i y i1 )<br />
1 8.155<br />
for an investment to triple in value if interest is earned at the rate<br />
2.718<br />
1 ?<br />
2 22.167<br />
of 5.75% compounded annually. 19.650 years<br />
?<br />
2.718<br />
2 ?<br />
3 60.257<br />
2.718<br />
29. Tripling Your Money Determine how much time is required<br />
? 4 163.794<br />
3 ?<br />
for an investment to triple in value if interest is earned at the rate<br />
?<br />
of 5.75% compounded daily. 19.108 years<br />
4 ?<br />
30. Tripling Your Money Determine how much time is required<br />
for an investment to triple in value if interest is earned at the rate<br />
of 5.75% compounded continuously.<br />
37. Writing to Learn Explain how the change ¢ y is related to<br />
19.106 years<br />
the slopes of the lines in Exercises 33 and 34. If the changes in x<br />
are constant for a linear function, what would you conclude<br />
about the corresponding changes in y?<br />
31. Cholera Bacteria Suppose that a colony of bacteria starts<br />
with 1 bacterium and doubles in number every half hour. How<br />
many bacteria will the colony contain at the end of 24 h?<br />
32. Eliminating a Disease Suppose that in any given year, the<br />
number of cases of a disease is reduced by 20%. If there are<br />
10,000 cases today, how many years will it take<br />
(a) to reduce the number of cases to 1000? 10.319 years<br />
(b) to eliminate the disease; that is, to reduce the number of<br />
cases to less than 1? 41.275 years<br />
Group Activity In Exercises 33–36, copy and complete the table<br />
for the function.<br />
38. Bacteria Growth The number of bacteria in a petri dish culture<br />
after t hours is<br />
B 100e 0.693t .<br />
(a) What was the initial number of bacteria present? 100<br />
(b) How many bacteria are present after 6 hours? 6394<br />
(c) Approximately when will the number of bacteria be 200?<br />
Estimate the doubling time of the bacteria. After about 1 hour,<br />
which is the doubling time<br />
37. Since x 1, the corresponding value of y is equal to the slope<br />
of the line. If the changes in x are constant for a linear function,<br />
then the corresponding changes in y are constant as well.