BULETINUL INSTITUTULUI POLITEHNIC DIN IAŞI
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Bul. Inst. Polit. Iaşi, t. LVIII (LXII), f. 3, 2012 17<br />
0<br />
⎧<br />
2<br />
ur + ( λ+ μ−α) ∂re −2α∂ zφθ + X<br />
r<br />
= 0,<br />
⎪<br />
−1<br />
⎨ 2uz + ( λ+ μ−α) ∂<br />
ze + 2 αr ∂<br />
r( rφθ ) + X<br />
z<br />
= 0, (32)<br />
⎪<br />
0<br />
⎪⎩ 4<br />
φθ + 2 α( ∂zur −∂<br />
ruz) + Yθ<br />
= 0.<br />
Here, we used the symbols ∂r,<br />
∂<br />
z<br />
to denote partial derivatives with respect to<br />
the position variable r, z , respectively. The dilatation e = ∇ · u in cylindrical<br />
coordinates and in the absence of variable θ , is given by<br />
−1<br />
e= r ∂<br />
r( rur)<br />
+∂<br />
zuz.<br />
0<br />
The symbols X<br />
r, Yθ , Xz<br />
denote body loadings and the operators<br />
i<br />
are defined<br />
through the operator by<br />
2<br />
∇ 0<br />
0 2 2 0 2<br />
2 0 2 4 0<br />
= ( μ + α)( ∇ + σ ); = ( γ + ε)( ∇ + σ 4<br />
).<br />
The role of the position variable x is played by the coordinates ( rz , ).<br />
The form of the second system in B is<br />
0<br />
⎧<br />
4<br />
ϕr + ( β + γ −ε) ∂rκ −2α∂ zuθ<br />
+ Yr<br />
= 0,<br />
⎪<br />
−1<br />
⎨ 4ϕz + ( β + γ −ε) ∂<br />
zκ + 2 αr ∂ r( ruθ<br />
) + Yz<br />
= 0,<br />
(33)<br />
⎪ 0<br />
⎩ 2<br />
uθ<br />
+ 2 α( ∂zϕr −∂<br />
rϕz) + Xθ<br />
= 0,<br />
−1<br />
where κ = ∇ · ϕ = r ∂<br />
r( rϕr) +∂<br />
zϕz, ϕ = ( ϕr, 0,<br />
ϕz),<br />
and Yr, Xθ<br />
, Yz<br />
0 are body<br />
loadings.<br />
5. The Second Axially-symmetric Problem of Micropolar Elasticity<br />
in the Case of Steady Vibrations<br />
This important problem of micropolar elasticity in the case of steady<br />
vibrations has as object of study the system (30). There are many references<br />
about the second axially-symmetric problem of micropolar elasticity in the case<br />
of steady vibrations. We quoute here Nowacki (1986), Kupradze (1986), and<br />
Dyszlewich (2004). The uncoupled form of system (30) may be found in<br />
Dyszlewicz (2004)<br />
2<br />
0 0<br />
⎧Ω uθ<br />
= 2 α( ∂zYr −∂rYz) −<br />
4<br />
Xθ<br />
,<br />
⎪<br />
0 0 0 0 0 0<br />
⎨ 3Ω φr =∂r( Θ Y ) −2 α∂z 3<br />
Xθ −<br />
2 3Yr<br />
,<br />
⎪<br />
⎩ Ω φ =∂ ( Θ Y ) + 2 α [ r ∂ ( rX )] − Y<br />
0<br />
3 z z 3 −1<br />
r θ 2 3 z<br />
,<br />
(34)<br />
where<br />
−1<br />
Y = ∇ · Y= r ∂ ( rY ) +∂ Y , Y=<br />
( Y , 0,<br />
Y ),<br />
r r z z r z