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Neutron Scattering

Neutron Scattering - JuSER - Forschungszentrum Jülich

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The Id rotor : solution based on 'free rotor' funetions<br />

The canonical strategy diagonalizes the hamiltonian matrix. It is important to chose an appropriate<br />

set of basis functions [4] .<br />

The simplest molecule consists of two atoms and allows two orientations in a double minimum<br />

potential (H2 , H20 . .) . The case was already considered in the section "Translational<br />

tunnelling " . Here we want to consider a mcthyl group, the most intensively studied system . It<br />

is characterized by its momentum of inertia () around its symmetry axis or - equivalently - by<br />

its rotational constant B = 20 .<br />

An obvious set of basis functions are the free rotor functions exp(ini~o) .<br />

In the single<br />

particle model the interaction with the surrounding is reflected in a static rotational potential<br />

V. To get the Hamiltonian H the kinetic rotational energy bas to be added<br />

H = _ OJ 2 + V<br />

r2<br />

d2<br />

- 20 jcp~ + V<br />

d 2<br />

-B d ;2 + V (17 .39)<br />

A dimensionless representation of the eigenvalue (Schrödinger) equation is<br />

with the scaled rotational potential V' =<br />

H<br />

B w<br />

E<br />

Bw<br />

(17 .40)<br />

n,<br />

V3 (1 - cos(3nço» (17 .41)<br />

n,-1<br />

The eigenfunetions are expanded into free rotor functions up to the order 2M+1<br />

ni--M<br />

with eigenvectors a. . Only a few matrix elements deviate from zero . They follow from orthognality<br />

relation of the angular functions<br />

exp(an~)h (~)exp(ana~)d<br />

exp(an~)h (~)exp(ana~)d<br />

a,exp(irreV) (17 .42)<br />

1 ; r ,<br />

Z 4'",<br />

y;t -<br />

4 d(Zts)<br />

d 2<br />

exp(incp) ~~2<br />

exp(irrup)dcp = -m2 S,zrn, (17 .43)<br />

17-15

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