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Neutron Scattering

Neutron Scattering - JuSER - Forschungszentrum Jülich

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to a volume V is simply a plane wave with wave vector K :<br />

ID'(r) = WE) _ exp(iK - r) . (5 .64)<br />

Using this expression, thé matrix element in thé double differential cross section (5 .27)<br />

can immediately be calculated :<br />

(KIexpiQ-rlr,)<br />

VJv d3rexp(i(Q+ - K)-?')=6(Q+r,-K) . (5 .65)<br />

The resulting delta function expresses the momentum conservation . Only if momentum<br />

is conserved the matrix element is 1-otherwise zero .<br />

In the second step we have to consider energy conservation .<br />

wave vector K is<br />

The energy of the atom with<br />

(5 .66)<br />

where ms , is thé mass of thé scattering atom . For thé évaluation of thé delta function<br />

in (5 .27) we need thé energy différence between thé states K and W .<br />

Because of thé delta<br />

function factor (5 .65) only such states with K' = K - Q have to be considered and for<br />

those thé energy différence is :<br />

(5 E, - E = - (Qz + 2Q ) .<br />

.67)<br />

2m .,<br />

With this result one can calculate the scattering function :<br />

S(Q, w) = E Pub (hw - h (Qz + 2Q - E)~ . (5 .68)<br />

2msc<br />

In thé limit of a large volume V, K becomes a continuons variable .<br />

thé component of K parallel to Q is relevant .<br />

Therefore, (5 .68) can be written as a onedimensional<br />

integral :<br />

In addition only<br />

S(Q, cv) = J<br />

dKP,6<br />

(hw<br />

- 1' (Qz +<br />

2QK))<br />

. (5 .69)<br />

2m sc<br />

The probability of a momentum state K follows from the Boltzmann distribution :<br />

1 1i2K2<br />

P, Z eXp ( 2m-kRT<br />

(5 .70)<br />

with thé state surr being<br />

z z<br />

Z = ~ dr exp _ ~ r,<br />

( 2m kBT)<br />

5- 2 1<br />

_ 2~rme~kB T .<br />

(5 .71)

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