Apostila Mec. Flu

Aula 15
Prof. MSc. Luiz Eduardo Miranda J. Rodrigues
Solução do Exercício 1
a) Massa específica da mistura: b) Velocidade em (3):
∑
ρ
Q me
= ∑Qms
1
⋅ Q
V1
+ ρ
2
⋅ QV
2
= ρ
3
⋅ ( QV
1
+ QV
2
Q = Q + Q
V 3 V1
V 2
ρ ⋅ Q
+ ρ
⋅ Q
= ρ ⋅ Q
1 V1
2 V 2 3 V 3
ρ1
⋅ Q
ρ =
3
V1
+ ρ ⋅ Q
Q
V 3
600 ⋅ 4 + 800 ⋅ 3
ρ
3
=
7
2
V 2
)
2400 +
ρ
3
=
7
4800
ρ
3
=
ρ 71
7
3
= 685, kg/m³
2400
v
v
4⋅Q
V 3
3
=
2
π ⋅ d
3
−3
4 ⋅ 7 ⋅10
3
=
2
π ⋅ 0,1
v 3
= 0,89m/s
c) Velocidade em (5):
4 ⋅ QV
3
vrec
2
⋅ d
v
5
=
=
π
rec
−3
4⋅7⋅10
2
π ⋅0,05
v 5
= 3,56m/s
Mecânica dos Fluidos