Apostila Mec. Flu

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Aula 12 Prof. MSc. Luiz Eduardo Miranda J. Rodrigues Solução do Exercício 2 v Equação da Continuidade 1 ⋅ A1 = v2 ⋅ A2 v1 ⋅ 20 = v2 ⋅10 v1 ⋅ 20 10 = v v2 = 2 ⋅ v 1 2 (IV) Substituir (IV) em (III) = (2 ⋅ v ) 2 − 2 1 1 2 2 = 4 ⋅ v1 − 1 2 = 3⋅ 1 25,2 v 25,2 v 25,2 v 25,2 3 = v 2 1 8,46 = v 1 v 1 = 2,9m/s Cálculo da Vazão: Q v = v 1 ⋅ A 1 Q v Q v Q v = 2,9 ⋅ 20 ⋅10 = 0,0058m³/s = 5,8 litros/s −4 Mecânica dos Fluidos
Aula 12 Prof. MSc. Luiz Eduardo Miranda J. Rodrigues Exercícios Propostos 1) Determine a altura da coluna da água no reservatório de grandes dimensões mostrado na figura. Dados: ρ h20 = 1000kg/m³ e g = 10m/s². (2) Aberto, nível constante H (1) ref v 1 =8m/s Mecânica dos Fluidos
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Mecânica dos Fluidos Aula 1 - Defi
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Aula 1 Prof. MSc. Luiz Eduardo Mira
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Mecânica dos Fluidos Aula 5 - Man
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Mecânica dos Fluidos Aula 6 - Man
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Mecânica dos Fluidos Aula 7 - Flut
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Page 133 and 134: Aula 8 Prof. MSc. Luiz Eduardo Mira
Page 137 and 138: Mecânica dos Fluidos Aula 9 - Aval
Page 141 and 142: Aula 10 Prof. MSc. Luiz Eduardo Mir
Page 157 and 158: Mecânica dos Fluidos Aula 11 - Equ
Page 183: Aula 12 Prof. MSc. Luiz Eduardo Mir
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Aula 17 Prof. MSc. Luiz Eduardo Mir
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Mecânica dos Fluidos Aula 18 - Exe
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Mecânica dos Fluidos Aula 20 - Rec
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