razlika kvadratak - MIM-Sraga

M-1-Razlika kvadrata
Rješenja i kompletni postupak
( x )( x ) ( x)
2 2
( )( )
7. Koristimo formulu za razliku kvadrata: A− B A+ B = A −B
27) 0.3 − 5 0.3 + 5 = 0.3 − 5 =
2 2
= ⋅x
− = → ⎡
⎣ = ⋅ =
2 2 2
0.3 25 0.3 0.3 0.3 0.9
2
0.09 25
= x −
⎤
⎦
2 2
2 2 2 2
⎛ 1 1 ⎞⎛ 1 1 ⎞ ⎛ 1 ⎞ ⎛1
⎞
28) ⎜1 x − y⎟⎜1 x + y⎟ = ⎜1
x ⎟ − ⎜ y ⎟ =
⎝ 2 3 ⎠⎝ 2 3 ⎠ ⎝ 2 ⎠ ⎝3
⎠
2
1⎞
2 2 1
1 ⎟ 2
( x ) ⎜ 3
( )
⎛
⎛ ⎞ 2 2
= ⎜ ⋅ − ⎟ ⋅ y =
⎝ ⎠ ⎝ ⎠
2 2
22 ⋅
22 ⋅
x y
2
⎛12 ⋅ + 1⎞
1
= ⎜ ⋅ − ⋅ =
2
⎟
⎝ ⎠ 3
2
⎛3⎞
4 1 2
= ⋅ − =
⎜ ⎟ x y
⎝2⎠
9
9 4 1 2
= x − y
4 9
2
( x )( x ) ( x)
2 2
29) 0.1 − 0.2 0.1 + 0.2 = 0.1 − 0.2 =
2 2
0.1 0.04
= ⋅x
− =
2
0.01 0.04
= x −
( x )( x ) ( x )
4 4 4 2 2
30) − 0.75 + 0.75 = − 0.75 =
x
42 ⋅
= − =
8
= −
x
0.5625
0.5625
3 3
( 0.1 − 0.3 )( 0.1 + 0. 3y) ( 0.1x ) ( 0.3y)
0.1 ( x ) 0.3
31) x y x
3 2 2
= − =
2 3 2 2 2
= ⋅ − ⋅ =
0.01 x 0.09y
32 ⋅
2
2
= ⋅ − = → ⎡0.3 = 0.3⋅ 0.3 = 0.9⎤
= 0.01x
−0.09y
6 2
y
⎣
⎦
M I M Sraga 2005
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