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M-1-Kvadrat binoma<br />

Rješenja i kompletni postupak<br />

34. Kvadriramo po pravilu: A+ B = A + 2⋅A⋅ B+ B i A− B = A −2⋅A⋅ B+<br />

B<br />

To pravilo možemo pisati i ovako:<br />

( ) ( )<br />

2 2 2 2 2 2<br />

( ) i ( )<br />

2 2 2 2 2<br />

I + II = I + 2⋅I ⋅ II + II I − II = I −2⋅I ⋅ II + II<br />

2<br />

( )<br />

( )<br />

2 2 2<br />

17) 2 + z = 2 + 2⋅2⋅ z+ z =<br />

= 4+ 4z+<br />

z<br />

2 2 2<br />

18) z− 2 = z −2⋅z⋅ 2 + 2 =<br />

2<br />

= − +<br />

2 2<br />

( x+ y)<br />

= x + 2 x 5y ( 5y)<br />

19) 5<br />

Još jednom isti zadatak:<br />

z<br />

2<br />

4z<br />

4<br />

( ) ( )<br />

( ) ( )<br />

2 2 2<br />

= x + xy+ y =<br />

2 2<br />

2<br />

2 2 2 2 2 2 2 2<br />

Primjeni pravilo:<br />

2 2<br />

⋅ ⋅ + =<br />

10 5<br />

= x + 10xy+<br />

25y<br />

19) x+ 5y = x + 2⋅x⋅ 5y+ 5y = x + 10xy+ 5 y = x + 10xy+<br />

25y<br />

i ovdje<br />

<br />

n n n<br />

( ) u našem slučaju: ( )<br />

2 2 2 2<br />

ab = a b 5y = 5 y = 25y<br />

20) 5x− y = 5x −2⋅5x⋅ y+<br />

y = 5 x − 10xy+ y = 25x − 10xy+<br />

y<br />

2 2 2 2 2 2<br />

ili možemo pisati i ovako:<br />

( ) ( )<br />

2 2 2<br />

5x− y = 5x −2⋅5x⋅ y+ y =<br />

5 10<br />

2 2 2<br />

= x − xy+ y =<br />

= 25x − 10xy+<br />

y<br />

2 2<br />

( ) ( )<br />

2 2 2<br />

21) 7x+ y = 7x + 2⋅7x⋅ y+ y =<br />

2 2 2<br />

= x + xy+ y =<br />

7 14<br />

= 49x + 14xy+<br />

y<br />

2 2<br />

2<br />

( x y) x x y ( y)<br />

2 2<br />

22) − 3 = −2⋅ ⋅ 3 + 3 =<br />

2 2 2<br />

= x − xy+ y =<br />

6 3<br />

= x − 6xy+<br />

9y<br />

2 2<br />

M.I.M.-Sraga -2003./2013.<br />

www.mim-sraga.com<br />

5<br />

© M.I.M-Sraga centar za poduku<br />

mim-sraga@zg.htnet.hr<br />

tel-01-4578-431

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