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Mathematics (09) Practice TestSECOND SAMPLE STRONG RESPONSE FOR OPEN-RESPONSEITEM ASSIGNMENT #2V b(r) = 4 3 πr 3r = d 2V b(d) = 4 3 π ⎝ ⎛ d2⎠ ⎞V b(d) = 4 33 πd 83V b(d) = 1 6 πd 3 in 3V cyl= πr 2 hh = 12 inr = 1 2 inV s= π⎛12⎞ ⎝ 2 ⎠ (12)V s= π⎛1⎞⎝ 4 ⎠ (12)V s= 3π in 3S(d) = 3V b (d) in 3 /secV sin 3 /footS(d) = 3⎛1⎞ ⎝ 6 πd 3 ⎠/(3π)S(d) = d 3 feet6 secS(0.5) = (0.5) 3 /6 ≈ 0.021S(1.0) = (1.0) 3 /6 ≈ 0.167S(1.5) = (1.5) 3 /6 ≈ 0.563S(2.0) = (2.0) 3 /6 ≈ 1.333S(2.5) = (2.5) 3 /6 ≈ 2.60495