20.08.2015 Views

process

K-theory and Noncommutative Geometry.pdf

K-theory and Noncommutative Geometry.pdf

SHOW MORE
SHOW LESS
  • No tags were found...

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

398 G. Garkusha and M. Prestranges over the annihilators of non-zero elements of E. Since R=I m is finitely presented,0 ¤ f 0 g factorises through one of the maps R=I ! R=P.E/. In particular,there is a non-zero morphism R=I m ! E showing that E 2 V fg .I /, as required.Given a module M ,wesetŒM WD fE 2 Inj R j Hom R .M; E/ D 0g; .M/ WD Inj R n ŒM :Remark 3.4. For any finitely generated ideal I we have: D fg .I / \ Spec R D D.I /and V fg .I / \ Spec R D V.I/. Moreover, D fg .I / D ŒR=I .If I;J are finitely generated ideals, then D.IJ / D D.I / \ D.J /. It follows fromProposition 3.3 and Remark 3.4 that D fg .I / \ D fg .J / D D fg .IJ /. Thus the setsD fg .I / with I running over finitely generated ideals form a basis for a topology onInj R which we call the fg-ideals topology. This topological space will be denoted byInj fg R. Observe that if R is coherent then the fg-topology equals the Zariski topologyon Inj R (see [14], [8]). The latter topological space is defined by taking the ŒM withM finitely presented as a basis of open sets.Theorem 3.5. (cf. Prest [14, 9.6]) Let R be a commutative ring, let E be an indecomposableinjective module and let P.E/ be the prime ideal defined before. Then E andE P.E/ are topologically indistinguishable in Inj fg R.Proof. This follows from Proposition 3.3 and Remark 3.4.Theorem 3.6. (cf. Garkusha–Prest [8, Theorem A]) Let R be a commutative ring.The space Spec R is dense and a retract in Inj fg R. A left inverse to the embeddingSpec R,! Inj fg R takes an indecomposable injective module E to the prime idealP.E/. Moreover, Inj fg R is quasi-compact, the basic open subsets D fg .I /, with I finitelygenerated, are quasi-compact, the intersection of two quasi-compact open subsets isquasi-compact, and every non-empty irreducible closed subset has a generic point.Proof. For any finitely generated ideal I we haveD fg .I / \ Spec R D D.I /(see Remark 3.4). From this relation and Theorem 3.5 it follows that Spec R is densein Inj fg R and that ˛ W Spec R ! Inj fg R is a continuous map.One may check (see [14, 9.2]) thatˇ W Inj fg R ! Spec R;E 7! P.E/;is left inverse to ˛. Remark 3.4 implies that ˇ is continuous. Thus Spec R is a retractof Inj fg R.Let us show that each basic open set D fg .I / is quasi-compact (in particular Inj fg R DD fg .R/ is quasi-compact). Let D fg .I / D S i2 Dfg .I i / with each I i finitely generated.It follows from Remark 3.4 that D.I / D S i2 D.I i/. Since I is finitely generated,

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!