Model Question Paper CET Physics - WIT Solapur
Model Question Paper CET Physics - WIT Solapur Model Question Paper CET Physics - WIT Solapur
(1) - 14 (2) 14 (3) -7 (4) 785. If a - b -c-a b -c + λ abc = 0 then λ is :-a -b c(1) -2 (2) 2 (3) 4 (4) -486. If A = 2 3 and B = 1 21 2 3 3 then :2 4(1) BA= 4 7 (2) BA= 4 9 89 15 7 15 148 14(3) AB= 8 15 12 (4) AB= 8 44 9 10 15 912 1087. If A = 1 k then A n =0 1(1) n nk (2) n k n0 n 0 n(3) 1 nk (4) 1 k n0 1 0 188. ( 1 – i ) ( 1 + 2i ) ( 2 – 3i ) =(1) √130 (2) √13 (3) 130 (4) 1389. (a + b ) (aω + bω 2 ) (aω 2 + bω) =(1) 6 (a 2 +b 3 ) (2) 3 (a 3 +b 3 ) (3) a 3 +b 3 (4) 0
90 If z - 2 > z – 4 then the correct statement is :(1) x > 3 (2) x > -3 (3) x . 1 (4) x > -191. If α, β are the roots of the equation x2 – 5x – 3 = 0 then the equation whose roots are1 , 1 will be :2 θ - 3 2 β - 3(1) 33x 2 + 4x + 1 = 0 (2) 33x 2 – 4x – 1 = 0(3) 33x 2 +4x + 1 = 0 (4) 33x 2 + 4x – 1 = 092. If x is real then the values ofx 2 + 14x + 9 is :x2 + 2x + 3(1) ( - ∞, - 5 ) ∪ ( 4, ∞ ) (2) [ - 5, 4] (3) [-4, 5] (4) [4, 5]93. The sun of numbers divisible by 7 and lies between 100 to 300 will be :(1) 5486 (2) 8588 (3) 5086 (4) 558694. The area of the triangle represent by z, iz, and z – iz will be :(1) 2 z 2 (2) z 2 (3) z 2 (4) 02_ _95. If z = x + iy then zz + 2(x + z) + c = 0 will represent :(1) a point (2) parabola (3) st-line (4) circle96. If x = 2√3i then x 4 + 4x 2 – 8x + 39 is equal to :(1) -20 (2) -52 (3) – 20 + 16i√3 (4) 20+16i√97. If one root of the equation 2x 2 – bx + c = 0 is square of the other then :(1) b 2 – 4ac = θ (2) ac (a + c + 3b) = b 3(3) ac = b 3 (4) none of these98. (a – b) 2 , (b – c) 2 , (c – a) 2 are in A.P. the 1 , 1 , 1____will be : a – b b – c c - a(1) in H.P. (2) in G.P. (3) in A.P. (4) none of these99. If the first term of an infinite G.P. scries is 1 and its every term is the sum of the nextsuccessive terms then fourth term will be :(1) 1_ (2) 1 (3) 1 (4) 116 8 4 2100. Correct statement is :(1) (AB) -1 = B -1 A -1 (2) (AB) T = A T B T (3) (AB) -1 = A -1 B -1 (4) none of these
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(1) - 14 (2) 14 (3) -7 (4) 785. If a - b -c-a b -c + λ abc = 0 then λ is :-a -b c(1) -2 (2) 2 (3) 4 (4) -486. If A = 2 3 and B = 1 21 2 3 3 then :2 4(1) BA= 4 7 (2) BA= 4 9 89 15 7 15 148 14(3) AB= 8 15 12 (4) AB= 8 44 9 10 15 912 1087. If A = 1 k then A n =0 1(1) n nk (2) n k n0 n 0 n(3) 1 nk (4) 1 k n0 1 0 188. ( 1 – i ) ( 1 + 2i ) ( 2 – 3i ) =(1) √130 (2) √13 (3) 130 (4) 1389. (a + b ) (aω + bω 2 ) (aω 2 + bω) =(1) 6 (a 2 +b 3 ) (2) 3 (a 3 +b 3 ) (3) a 3 +b 3 (4) 0
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