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Model Question Paper CET Physics - WIT Solapur

Model Question Paper CET Physics - WIT Solapur

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(1) 14 4 - 224 -22 1422 -14 4(2) 14 4 - 224 -22 14-22 14 4(3) - 14 4 224 22 -1422 - 14 4(4) 14 - 4 - 22- 4 -2 2 14-22 14 - 480. The A.M. of any two numbers is 16 and their H.M. = 63 then their G.M. will be :4(1) √3 (2) 6 √3 (3) √7 (4) 6 √781. The sum of n terms of 1.2.3 + 2.3.4 will be :(1) n ( n + 1 ) ( n + 2 ) ( n + 3 )4(2) 2n ( n + 1 ) ( n + 2 ) ( n + 3 )3(3) ( n + ) ( n + 2 ) ( n + 3 )4(4) n ( n – 1 ) ( n – 2 ) ( n – 3 )482.Out of 14 players there are 5 bowlers. Then the total number of ways of selecting a team of 11players of which at least 4 are bowlers are :(1) 275 (2) 264 (3) 263 (4) 26583. If ( 1 + x) n = C 0 + c 1 x + C 2 x 2 + ….+ C n x n then the value of C 1 + 2C 2 + 3C 3 + 4C 4 + ….+ nC nwill be :(1) 2 n-1 (2) n . 2 n-1 (3) 2 n (4) 084. If the coefficients of the second third and fourth terms in the expansion of ( 1 + x) 2n are inA.P. then 2n 2 – 9n is :

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