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Application for the Reassessment of a Hazardous Substance under ...

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[0.625 x {(0.018 x 0.05) + (2.68 x 0.05) + (0.26 x 0.1)} x 0.3] / 70 =(0.1006 x 0.30) / 70 = 0.0302 / 70 = 0.0004 mg/kg b.w.Inhalation exposures:For <strong>the</strong> estimation <strong>of</strong> inhalation exposures APVMA (2008b) noted that as long as <strong>the</strong>operator did not walk back through <strong>the</strong> efflux stream <strong>the</strong>n <strong>the</strong> highest airborneconcentration <strong>of</strong> dichlorvos should be <strong>the</strong> use rate, 50 mg/m 3 , with a TWA <strong>of</strong> 25 mg/m 3 .The APVMA estimated <strong>the</strong> duration <strong>of</strong> exposure on <strong>the</strong> application times from <strong>the</strong>manufacturer‘s specification <strong>for</strong> <strong>the</strong> manual pressure gun (70 sec/300 m 3 ; i.e. (375/300x 70) = 87.5 seconds, (3750/300 x 70) = 875 seconds and (12500/300 x 70) = 2917seconds <strong>for</strong> <strong>the</strong> New Zealand Scenarios) <strong>for</strong> larger industrial spaces. [These valueswere rounded to 1.5, 15 and 50 minutes, equivalent to 0.025, 0.25 and 0.83 hourrespectively <strong>for</strong> <strong>the</strong> model.] The operator‘s ventilation rate was taken as 1m 3 /hour <strong>for</strong>light activities (US EPA, 1996; Original not sighted).For 375 m 3 – inhalation exposure:= airborne concentration (TWA) [mg/m 3 ] x ventilation rate [m 3 /hr] x duration [hr]25 x 1 x 0.025 = 0.625 mg a.i./personThen accepting <strong>the</strong> inhalation absorption factor <strong>of</strong> 100%, and dividing by 70 kg b.w.,<strong>the</strong> systemic dose will be:(0.625 x 1.00) / 70 = 0.0089 mg/kg b.w.If RPE is considered to mitigate exposures, APVMA used 10% penetration <strong>of</strong> half-facerespirators; 2% penetration <strong>of</strong> full-face respirators; and, no penetration <strong>of</strong> air-hoserespirators or SCBA (Thongsinthusak et al., 1993; Original not sighted):With half-face (protection factor applied, 0.1):(25 x 1 x 0.025) / 70 = (0.625 x 0.10) / 70 = 0.0625 / 70 = 0.0009 mg/kg b.w.For 3750 m 3 – inhalation exposure:25 x 1 x 0.25 = 6.25 mg a.i./person.Then accepting <strong>the</strong> inhalation absorption factor <strong>of</strong> 100%, and dividing by 70 kg b.w.,<strong>the</strong> systemic dose will be:(6.25 x 1.00) / 70 = 0.0893 mg/kg b.wDichlorvos reassessment – application Page 358 <strong>of</strong> 436

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