UseSciCalculator Tutorial

USE OF THE SCIENTIFIC CALCULATOR p.5other Casios:Mode 1 is FIXMode 2 is SCIMode 3 is NORMUse Mode 2 9 to show scientific notation with 9 digits.Use Mode 3 1 to show nonexponential which automatically switches to sci. notationwhen number is less than .01Use Mode 3 1 to show nonexponential which automatically switches to sci. notationwhen number is less than . 000001TI 25x: Press X 1 EE = to switch to scientific notationPress 2 nd EE to switch back to nonexponential formSharp, & some others: INV EE converts numbers to nonexponential form1 X EE converts numbers to scientific notationCertain models: Use 2 nd F and FSEwhere F or FD means floating decimal(normal display)S or SCI means scientific notationE means engineeringRules for handling significant figures for log, antilog, ln and antiln:When you find the log of a number, the number of significant figures of that number is thenumber of decimal places of the answer.Example 1: log 5.1 = ? Ans. 0.715.1 has 2 sig. fig. so ans 0.707570... should be rounded to 2 decimal places.Example 2: log 0.0327 = ? Ans. –1.4850.0327 has 3 sig. fig. so –1.4854... should be rounded to 3 decimal places.Example 3: log 2x10 –2 = ? Ans. –1.72x10 –2 has 1 sig. fig. so ans –1.6989... should be rounded to 1 decimal place.When you find the antilog of a number, the number of decimal places of that number inNONEXPONENTIAL FORM is the number of significant figures of the answer.Example 4: antilog 3.2x10 –2 = ?You must first convert 3.2x10 –2 to nonexponential form: 0.0320.032 has 3 decimal places so ans 1.076465... should be rounded to 1.08 (3 sig. fig.)Significant figures for ln and antiln work the same way:Example 5: ln 7.5 = 2.01 (7.5 has 2 sig. fig. so ans should be in 2 decimal places.)Example 6: antiln 2.7x10 –1 = 1.3 (2.7x10 –1 = 0.27 has 2 decimal places, so ans is in 2 sig.fig.)

USE OF THE SCIENTIFIC CALCULATOR p.6EXTRA CALCULATOR DRILLPerform the following calculations, using your calculator. For simplicity, round your answers to2 significant figures. Practice for sig. fig. is provided elsewhere. GET HELP IMMEDIATELYif you are not getting the right answers. YOU CANNOT AFFORD TO WAIT!9. (2.5 x 10 4 ) (3.1 x 10 6 ) = = 7.75 x 10 10 = 7.8 x 10 1010. (− 3.7 x 10 8 ) (4.9 x 10 -7 ) = = − 1.813 x 10 2 = −1.8 x 10 211.12.⎛ ⎞⎛⎞⎜4.7 x 10 6⎟⎜1.5 x 10 8 ⎟⎝ ⎠⎝⎠⎛ ⎞⎛4 ⎞⎜2.6 x 10 9⎟⎜3.8 x 10 ⎟⎝ ⎠⎝⎠⎛ ⎞⎜ 3.1 x 10 7 + 8.2 x 10 5⎟⎜7 ⎟⎝ 5.1 x 10 ⎠= 7.135627 = 7.1= 6.239215 x 10 −1 = 6.2 x 10 − 113.⎜⎛⎝⎜⎛⎝1.7 x 104.7 x 10 -8⎟⎞⎜⎛⎠⎝2+⎛⎟⎞⎜⎠ ⎝2.4 x 10 -4⎟⎞⎠3.7 x 10 - 8⎞⎟⎠= 8.680844 x 10 5 = 8.7 x 10 514.1010714xx10-10-621= 10 815. 3.7 x 10 − 4 10 19 = 3.7 x 10 4210 − 2716. 2.1 x 10 − 3 1 10 − 8 = 2.1 x 10 − 410 − 7 1For Gen Chem I (Chem 121) students, you can stop here. You will not be handling log and lnquestions in the first semester.For Gen Chem II (Chem 123) students, you DO need to be able to do log problems such as theones below.17. log (4 x 10 –8 ) = – 7.418. antilog (– 6.92) = 1.2 x 10 –719. ln 3.2 x 10 –4 = –8.0471896 (recorded as –8.05)20. antiln (–2.78 x 10 –2 ) = 0.9725828 (recorded as 0.9726)