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Three-vector and scalar field identities and uniqueness theorems in ...

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component of the second four-volume <strong>in</strong>tegral of Eq. (37),<strong>and</strong> the third four-volume <strong>in</strong>tegral of Eq. (38) followsfrom that same term’s α = i spatial components by compar<strong>in</strong>gthe implied sum on i for each of the j = 1, 2, 3components with the components of the <strong>vector</strong> triplecross product <strong>in</strong> Eq. (38). If we make the change of variables[us<strong>in</strong>g the components of the four-curl of A µ , thatis, Maxwell’s <strong>field</strong> tensor F µν , see Eqs. (55) <strong>and</strong> (56)]withE = −∇φ − ∂A , B = ∇ × A, (39)∂t<strong>and</strong> the change of variables [us<strong>in</strong>g the four-divergence ofA µ , see Eq. (57)] withwe can reduce Eq. (38) to∫A(x) = − ∇C = ∇ · A + 1 c 2 ∂φ∂t , (40)V 4′− 1 ∫∂c 2 ∂t∫+ ∇ ×C(x ′ )G(x, x ′ )d 4 x ′V ′4V ′4E(x ′ )G(x, x ′ )d 4 x ′B(x ′ )G(x, x ′ )d 4 x ′ . (41)We can move the unprimed ∇ operator <strong>in</strong>to the first(primed) <strong>in</strong>tegral of Eq. (41), <strong>and</strong> then as for Eq. (25),we can express the argument of the <strong>in</strong>tegral as∇(C(x ′ )G(x, x ′ )) = −C(x ′ )∇ ′ G(x, x ′ )(42a)= −∇ ′ (C(x ′ )G(x, x ′ )) + (∇ ′ C(x ′ ))G(x, x ′ ), (42b)because the unprimed gradient of C(x ′ ) is zero <strong>and</strong> theGreen’s function property (22a) is used <strong>in</strong> Eq. (42a).Note that∫V ′ ∇ ′ (C(x ′ )G(x, x ′ ))dV ′ = 0 (43)over the <strong>in</strong>f<strong>in</strong>ite three-volume V ′ for the <strong>scalar</strong> <strong>field</strong>C(x ′ ), which is assumed to vanish sufficiently rapidlyat <strong>in</strong>f<strong>in</strong>ity because A <strong>and</strong> φ are assumed to do so also.Therefore, only the second term of Eq. (42b) contributesto Eq. (41). If we use the result (25b) on the second <strong>in</strong>tegralof Eq. (41), assume that E is bounded <strong>in</strong> time, <strong>and</strong>use Eq. (10b) <strong>and</strong> the surface <strong>in</strong>tegral argument that ledto Eq. (13) on the third <strong>in</strong>tegral of Eq. (41), we obta<strong>in</strong>the desired three-<strong>vector</strong> <strong>field</strong> identity∫A(x) =V ′4(−∇ ′ C(x ′ ) − 1 ∂E(x ′ )c 2 ∂t ′)+ ∇ ′ × B(x ′ ) G(x, x ′ )d 4 x ′ . (44)In a similar fashion a <strong>scalar</strong> component of the identityEq. (69) of Ref. 6 can be obta<strong>in</strong>ed as follows:[ ∫A 0 (x) = − ∂ 0 ∂ νA ′ ν (x ′ )G(x, x ′ )d 4 x ′V 4′](A∮Σ ν (x ′ )n ′ ν)G(x, x ′ )dΣ ′′−[ ∫(− ∂ α ∂ ′α A 0 (x ′ ) − ∂ ′ 0 A α (x ′ ) ) G(x, x ′ )d 4 x ′V 4′]+ (A∮Σ α (x ′ )n ′ 0 − A 0 (x ′ )n ′α )G(x, x ′ )dΣ ′ .′(45)We adopt three-<strong>vector</strong> notation, allow the four-volumeV 4 ′ to exp<strong>and</strong> to <strong>in</strong>clude all M<strong>in</strong>kowski space-time, <strong>and</strong>set A 0 = (φ/c) so that Eq. (45) simplifies toφ(x)c∫∂∂t= 1 c∫− ∇ ·V 4′(∇ ′ · A(x ′ ) + 1 ∂φ(x ′ ))c 2 ∂t ′V ′4( ∇ ′ φ(x ′ )+ 1 c cG(x, x ′ )d 4 x ′∂A(x ′ ))∂t ′ G(x, x ′ )d 4 x ′ .(46)The same change of variables, Eqs. (39) <strong>and</strong> (40), reducesEq. (46) toφ(x)c= 1 ∫∂C(x ′ )G(x, x ′ )d 4 x ′c ∂t V 4′+ 1 ·∫c ∇ E(x ′ )G(x, x ′ )d 4 x ′ . (47)V ′4We can move the unprimed ∂/∂t operator <strong>in</strong>to thefirst (primed) <strong>in</strong>tegral of Eq. (47), <strong>and</strong> then, similar toEq. (25), we can express the <strong>in</strong>tegr<strong>and</strong> as:∂(C(x ′ )G(x, x ′ ))∂t= − C(x ′ ) ∂G(x, x′ )∂t ′(48a)= − ∂(C(x′ )G(x, x ′ ))∂t ′ + ∂C(x′ )∂t ′ G(x, x ′ ), (48b)because the unprimed time derivative of C(x ′ ) is zero;<strong>and</strong> the Green’s function property (22b) was used <strong>in</strong>Eq. (48a). A time <strong>in</strong>tegration of the first term ofEq. (48b) can be assumed to vanish as t ′ → ±∞ for the<strong>field</strong> C, which is assumed to be bounded <strong>in</strong> time becauseA <strong>and</strong> φ are assumed to do so also. Therefore, only thesecond term of Eq. (48b) contributes to Eq. (47). We useEq. (10a) <strong>and</strong> the surface <strong>in</strong>tegral argument which led toEq. (13) on the second <strong>in</strong>tegral of Eq. (47) to obta<strong>in</strong> thedesired <strong>scalar</strong> <strong>field</strong> identityφ(x)c= 1 c∫V ′4( ∂C(x ′ ))∂t ′ + ∇ ′ · E(x ′ ) G(x, x ′ )d 4 x ′ .(49)7

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