Copyright © by SIAM. Unauthorized reproduction of this article is ...
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1844 V. ANDRIEU, L. PRALY, AND A. ASTOLFILetV (x) = ω ∞ ϕ ∞ (V m (x))V ∞ (x)+ [1 − ϕ ∞ (V m (x))] ϕ 0 (V m (x)) V m (x)+ω 0 [1 − ϕ 0 (V m (x))] V 0 (x) ,where ϕ 0 and ϕ ∞ are C 1 nondecreasing functions sat<strong>is</strong>fying(E.3)(E.4)ϕ 0 (s) = 0 ∀ s ≤ 1 2 v 0, ϕ 0 (s) = 1 ∀ s ≥ v 0 ,ϕ ∞ (s) = 0 ∀ s ≤ v ∞ , ϕ ∞ (s) = 1 ∀ s ≥ 2v ∞ .Then V <strong>is</strong> C 1 , positive definite, and proper. Moreover, <strong>by</strong> construction,⎧ω 0 V 0 (x) ∀ x : V m (x) ≤ 1 2 v 0 ,⎪⎨V (x) =⎪⎩ϕ 0 (V m (x)) V m (x)+ω 0 [1 − ϕ 0 (V m (x))] V 0 (x)∀ x :12 v 0 ≤ V m (x) ≤ v 0 ,V m (x) ∀ x : v 0 ≤ V m (x) ≤ v ∞ ,ω ∞ ϕ ∞ (V m (x))V ∞ (x) + [1 − ϕ ∞ (V m (x))] V m (x)∀ x : v ∞ ≤ V m (x) ≤ 2 v ∞ ,ω ∞ V ∞ (x) ∀ x : V m (x) ≥ 2 v ∞ .Thus for each i in {1,...,n},(E.5)and(E.6)∂V∂x i(x) = ω ∞∂V ∞∂x i(x)∀ x : V m (x) > 2 v ∞∂V∂x i(x) = ω 0∂V 0∂x i(x) ∀ x : V m (x) < 1 2 v 0 .Since ∂V∞∂x iand ∂V0∂x iare homogeneous in the standard sense, <strong>th<strong>is</strong></strong> proves that∂Vfor each i in {1,...,n},∂x i<strong>is</strong> homogeneous in the bi-limit, with weights r 0and r ∞ and degrees d V0 − r 0,i and d V∞ − r ∞,i .3. It remains to show that the Lie derivative <strong>of</strong> V along f <strong>is</strong> negative definite.To <strong>th<strong>is</strong></strong> end note that, for all x such that 1 2 v 0 ≤ V m (x) ≤ v 0 ,∂V∂x (x)f(x) = ϕ′ 0(V m (x)) [V m (x) − ω 0 V 0 (x)] ∂V m∂x (x)f(x)+ ω 0 [1 − ϕ 0 (V m (x))] ∂V 0∂x (x)f(x)+ϕ 0(V m (x)) ∂V m∂x (x)f(x)and, for all x such that v ∞ ≤ V m (x) ≤ 2 v ∞ ,∂V∂x (x)f(x) = ϕ′ ∞(V m (x)) [ω ∞ V ∞ (x) − V m (x)] ∂V m∂x (x)f(x)+ ω ∞ ϕ ∞ (V m (x)) ∂V ∞∂x (x)f(x) + [1 − ϕ ∞(V m (x))] ∂V m∂x (x)f(x) .By (D.2), (E.1), (E.2), (E.3), and (E.4), these inequalities imply∂V(x) f(x) < 0 ∀ x ≠ 0 ,∂xwhich proves the claim.<strong>Copyright</strong> © <strong>by</strong> <strong>SIAM</strong>. <strong>Unauthorized</strong> <strong>reproduction</strong> <strong>of</strong> <strong>th<strong>is</strong></strong> <strong>article</strong> <strong>is</strong> prohibited.