Physics Spring Final Study Guide - thecubscientist.com

Physics Spring Final Study Guide1. The gravitational potential energy that is possessed by an object isdependent on the object’s:a. accelerationb. momentumc. positiond. speede. elastic potential energy2. As a ball falls freely toward the ground, the sum of its kinetic andgravitational potential energy:a. decreasesb. increasesc. remains the same3. A spring with a spring constant of 4.0 N/m is compressed by a force of1.2 N. What is the elastic potential energy stored in this compressedspring?a. 0.18 Jb. 0.36 Jc. 0.60 Jd. 4.8 Je. 5.9J4. The work done in lifting a 1 kg apple one meter near the Earth’s surfaceis approximately:a. 0.01 Jb. 1 Jc. 10 Jd. 100 Je. 1000 JPhysics Spring Final Review Guide

5. A railroad car of mass m is moving with speed v when it collides withand connects to a second railroad car of mass 3m, initially at rest, asshown below. How do the speed and kinetic energy of the connectedcars compare to those of the single car of mass m before the collision?Speed Kinetic Energya. Less Lessb. Less The samec. The same Lessd. The same The samee. Greater The same6. Which of the following is true of the conservation of momentum andkinetic energy?a. Momentum is conserved only in inelastic collisionsb. Momentum is conserved only in elastic collisionsc. Kinetic energy is conserved only in inelastic collisionsd. Kinetic energy is conserved only in elastic collisionse. Both require the same conditions in order to be conservedPhysics Spring Final Review Guide

7. A block of mass 3 kg slides along a horizontal surface that has negligiblefriction except for one section, as shown below. The block arrives at therough section with a speed of 5 m/s and leaves it 0.5 s later with a speedof 3 m/s. What is the magnitude of the work done by the frictional forceexerted on the block by the rough section of the surface?a. 24 Jb. 16 Jc. 8 Jd. 6 Je. 3 J8. In problem #7 above, what is the magnitude of the frictional forceexerted on the block by the rough section of the surface?a. 30 Nb. 12 Nc. 4.5 Nd. 4 Ne. 3 NPhysics Spring Final Review Guide

9. A block released from rest at position A slides with negligible frictiondown an inclined track, around a vertical loop, and then along ahorizontal portion of the track as shown below. The block never leavesthe track. After the block is released, in which of the followingsequences of positions is the speed of the block ordered from fastest toslowest?a. B C D Eb. B E C Dc. D C E Bd. E B C De. E D C B10. Refer to the situation in problem #9 above. Which of the following istrue of the net force on the block when it is at position C?a. It is directed vertically downwardb. It is directed vertically upward onlyc. It is directed to the left onlyd. It is directed to the right onlye. It has components both to the left and vertically downwardPhysics Spring Final Review Guide

11. A person throws a marble straight up into the air, releasing it a shortheight above the ground and catching it at that same height. If airresistance is negligible, which of the following graphs of position yversus time t is correct for the motion of the marble as it goes up andthen comes down?Physics Spring Final Review Guide

Sample Free Response Questions (FRQs)Sample FRQ 1: Momentum and Kinematics Model (2D)Physics Spring Final Review Guide

Sample FRQ 2: Momentum and EnergyPhysics Spring Final Review Guide

Sample FRQ 3: Kinematics and MomentumPhysics Spring Final Review Guide

Sample FRQ 4: Energy and MomentumPhysics Spring Final Review Guide

Sample FRQ 5: Momentum / KinematicsPhysics Spring Final Review Guide

Study Guide Key1. C Definition of Gravitational Potential Energy2. C Conservation of Energy3. A Spring potential energy4. C Gravitational potential energy5. A Conservation of Momentum / Definition of Kinetic Energy6. D Conservation of Momentum & Elastic vs. Inelastic Collisions7. A W = change in kinetic energy8. B W=Fd, use kinematics to find d9. B Conservation of Energy10. E Centripetal Force11. B KinematicsFRQ 1 Solutiona. Impulse = 12 Nsb. v horizontal = 2.4 m/sci. v after = 2 m/scii. To the rightd. Change in K = K final – K initial = 154 Je. Distance between two objects = 0.2 m (x block = 1.2 m, x cube = 1m)FRQ 2 Solutiona. PE spring = 50 Jb. v c = 4.58 m/sc. v final = 3.05 m/sd. d = 1.16 mFRQ 3 Solutiona. t total = 3.6 sbi. v Afinal = 1.2 m/sbii. To the rightc. The collision is NOT elastic (K initial = 3125 J, K final = 2484 J; loss ofkinetic energy)Physics Spring Final Review Guide

FRQ 4 Solutiona. Mgh = 1 2 M ( 3.5v 0) 2 , therefore, h = 3.522b. v = 0.5 v 02c. μ = 2v 0Dgd. The collision is inelastic; there is a loss of kinetic energy (K = 3Mv 02)FRQ 5 Solutiona. v 2after = 0.5 m/s, to the rightb. m = 3.1 kgc. a = -0.73 m/s 2d. d total = 5.5 me. h = 0.12 mv 02gPhysics Spring Final Review Guide