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Determining Percent Composition - Delsea

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Date:<strong>Percent</strong> <strong>Composition</strong>1. Carbon Dioxide = CO2Element # of Atoms Atomic Mass Total Atomic%<strong>Composition</strong>Carbon 1 12 12 27.27Oxygen 2 16 32 72.7344 1002. Sodium Nitrate = NaNO3Elements # of Atoms Atomic Mass Total Atomic%<strong>Composition</strong>Sodium 1 23 23 27.06Nitrogen 1 14 14 16.47Oxygen 3 16 48 56.4785 1003. Calcium Nitrate = Ca(NO3)2Elements # of Atoms Atomic Mass Total Atomic%<strong>Composition</strong>Calcium 1 40 40 24.39Nitrogen 2 14 28 17.07Oxygen 6 16 96 58.54164 1004. SIlver Sulfate = Ag2SO4Elements # of Atoms Atomic Mass Total Atomic%<strong>Composition</strong>Silver 2 108 216 69.23Sulfur 1 32 32 10.26Oxygen 4 16 64 20.51312 100


Date:<strong>Percent</strong> <strong>Composition</strong>€€€5. A sample of a compound contains 28 g iron and 12 g oxygen. What is the percentcomposition of this compound?28g +12g = 40g total compound % Iron = 28g x100 = 70.00%40g70.00% + 30.00% =100%6. A sample of sodium/oxygen compound contains 53 g sodium and 37 g oxygen.What is the percent composition?€53g + 37g = 90g total compound58.89% + 41.11% =100%% Oxygen = 12g x100 = 30.00%40g% Sodium = 53g x100 = 58.89%90g% Oxygen = 37g x100 = 41.11%90g7. A compound contains 2 moles of sodium and 2 moles of oxygen. What is thepercent composition of sodium and€oxygen in this compound?2mol Na1x23g Na2mol O1x 16g O1mol O = 32g O€Fe 2O€31mol Na = 46g Na46g + 32g = 78g total compound % Sodium = 46g x100 = 58.97%€78g58.97% + 41.03% =100%% Oxygen = 32g x100 = 41.03%78g8. What is the percent composition of iron and oxygen in iron (III) oxide?2mol Fe1x56g Fe€3mol O1x 16g O1mol O = 48g O€€CuSO 41mol Fe =112g Fe112g + 48g =160g total compound€70.00% + 30.00% =100%% Iron = 112g x100 = 70.00%160g% Oxygen = 48g x100 = 30.00%160g9. What is the percent composition of copper sulfate?112g + 48g =160g total compound1mol Cu 64g Cux = 64g Cu €1 1mol Cu1mol Sx 32g S% Iron = 112g x100 = 70.00%1 1mol S = 32g S160g€4mol Ox 16g O% Oxygen = 48g x100 = 30.00%1 1mol O = 64g O 160g70.00% + 30.00% =100%

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