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14. starptautiskā konference 2012 - Latvijas Jūras akadēmija

14. starptautiskā konference 2012 - Latvijas Jūras akadēmija

14. starptautiskā konference 2012 - Latvijas Jūras akadēmija

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Proceedings of 14th International conference „Maritime Transport and Infrastructure - <strong>2012</strong>”Thereforeor (Fig. 1)2tg2ytg tg 2 221tg 1y(1)ytg .x(2)We arrive at first order homogenous (nonlinear) differential equation:2yy21yx2 2xy y1 y(3)From the equation (3) we get:2 x x yy y(4)and introduce new unknown function:yu ; y ux;y ux u , wherexduu (5)dxAfter introduction of new variables in the equation (4), we separate variable and integrate:ududx ln C22 (6)1u 1u 1xFor the integral at the left side of equation we make substation of integration variable:2 21 u t ; 2udu 2tdt(7)and by integration we arrive at: ln t 1 ln x ln C . (8)Applying formulas (5) and (7), from (8) we get: y 1 1 x 2Cx. (9)After removing square root and making changes in constant C, we arrive at parabolic equation:y22 2Cx C . (10)When parabola (10) rotates around Ox axis a surface is created, which is called a rotation paraboloid.Problem 2. Radioactivity. The disintegration speed of radium is proportional to quantity ofsubstance Q. We know that after time of t 1 only half of the initial quantity Q 0 is left. Calculate amountof radioactive radium left after time of t .10t 1119

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