Algebra/Trig Review - Pauls Online Math Notes - Lamar University

Algebra/Trig ReviewFrom this we can see that1 3 5cos⎛ − π⎞⎜− =2 ⎟⎝ ⎠ 63.− ⎛ ⎞sin ⎜−⎟⎝ 2 ⎠1 1SolutionThe restrictions that we put on θ for the inverse cosine function will not work for theinverse sine function. Just look at the unit circle above and you will see that between0 and π there are in fact two angles for which sine would be 1 2and this is not whatwe want. As with the inverse cosine function we only want a single value.Therefore, for the inverse sine function we use the following restrictions.−1π πθ = sin ( x)−1 ≤ x≤1 and − ≤θ≤2 2By checking out the unit circle© 2006 Paul Dawkins 79http://tutorial.math.lamar.edu/terms.aspx