Answers - Pearson Global Schools
Answers - Pearson Global Schools
Answers - Pearson Global Schools
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2ybiyy2xy x(x 2)0yx2x20y3xx3y2xyii 1iii x(x 1 2) 5 2__ 3 xc i yFurther Pure Mathematics450y0yyyy3xxx4x8xdy x 2 1 0 1ii 3iii x 2 5 (x 1 1)(x 2 1) 2iy0y x 2 (1 x)1yxy (x 1)(x 1) 2x2x0yy3xx8xeii 2iii x 2 (1 2 x) 5 2__ 2 xiy4.4Exercise 4D1 a i yy x 2y1x04y x(x 4)x1 0 1xii 1iii x(x 2 4) 5__ 1 xy = x(x 2 2 1)ii 3iii x 2 5 x(x 2 2 1)10© <strong>Pearson</strong> Education Ltd 2010