Solutions for 02402 exam 15. December 20111

the correct answer can only be 3: F 0.05 (2, 6) = 5.14, shifts have significant influence on’down time’Exercise XIIA fast-food chain uses a biological degradable material for packaging their burgers.The thermal conductivity of the material is an important feature. The data in thetable below comes from an experiment where thermal conductivity is measured as afunction of the material density. It is assumed that the relationship can be describedby a simple linear model. The following values are measured:Material density (g/cm 3 ) .175 .220 .225 .226 .250 .277Thermal conductivity (W/mK) .0480 .0525 .0540 .0535 .0570 .0610Some computational statistics:¯x = 0.2288 , ȳ = 0.05433 , S xx = 0.005767, S yy = 0.00009583 and S xy = 0.0007383The following lines were run in R:x=c(.175,.220,.225,.226,.25,.277)y=c(.048,.0525,.054,.0535,.057,.061)summary(lm(y~x))with the following results: (However, two of the values have been substituted by ”A”and ”B”) :Call:lm(formula = y ~ x)Residuals:1 2 3 4 5 65.590e-04 -7.024e-04 1.575e-04 -4.706e-04 -4.332e-05 4.998e-04Coefficients:Estimate Std. Error t value Pr(>|t|)(Intercept) 0.025036 A 14.42 0.000134 ***x 0.128031 B 17.03 6.97e-05 ***---Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1Residual standard error: 0.0005709 on 4 degrees of freedomMultiple R-squared: 0.9864, Adjusted R-squared: 0.983F-statistic: 290 on 1 and 4 DF, p-value: 6.973e-0514