Chapter 17 - Light and Image Formation
Chapter 17 - Light and Image Formation Chapter 17 - Light and Image Formation
Announcements Reflection and Refraction Image Formation Final QuestionsQuestionA diverging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from the lens. Find the image distanceand describe the image.AnswerBecause the lens is a diverging lens, its focal length is negativeBecause the lens is diverging, we expect it to form an upright, reduced, virtual image for any object positionUsing the thin lens equation 1/p + 1/q = 1/f and solving for q we find thatq =( 1q − 1 ) −1 ()1=p −10.0 cm − 1 −130.0 cm= −7.50 cmThe magnification of the image isM = − q p= −−7.50cm30.0 cm = +0.250This result confirms that the image is virtual, smaller than the object, and uprightLight and Image Formation
Announcements Reflection and Refraction Image Formation Final QuestionsHomework Assignment 10Homework for Chapters 16 and 17 (due at the beginning of class on Tuesday, November 23)Chapter 16: Q9, Q13, Q23, E2, E8Chapter 17: Q2, Q10, Q14, Q18, E6, E10Light and Image Formation
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Announcements Reflection <strong>and</strong> Refraction <strong>Image</strong> <strong>Formation</strong> Final QuestionsHomework Assignment 10Homework for <strong>Chapter</strong>s 16 <strong>and</strong> <strong>17</strong> (due at the beginning of class on Tuesday, November 23)<strong>Chapter</strong> 16: Q9, Q13, Q23, E2, E8<strong>Chapter</strong> <strong>17</strong>: Q2, Q10, Q14, Q18, E6, E10<strong>Light</strong> <strong>and</strong> <strong>Image</strong> <strong>Formation</strong>
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