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3. An aqueous solution of potassium chloride, KCl, IS MIXED with an aqueous solution ofammonium sulfate, (NH 4 ) 2 SO 4 . Which one of <strong>the</strong> following represents <strong>the</strong> completemolecular equation?KCl (aq) + (NH 4 ) 2 SO 4 (aq) a. 2 KCl (aq) + (NH 4 ) 2 SO 4 (aq) K 2 SO 4 (s) + 2 NH 4 Cl (aq)b. 2 KCl (aq) + (NH 4 ) 2 SO 4 (aq) K 2 SO 4 (aq) + 2 NH 4 Cl (s)c. 2 KCl (aq) + (NH 4 ) 2 SO 4 (aq) K 2 SO 4 (s) + 2 NH 4 Cl (s)d. 2 K + (aq) + CO 3 -2 (aq) K 2 CO 3 (s)e. No reaction.4. What is <strong>the</strong> maximum number electrons allowed for <strong>the</strong> n = 3 shell?a. 6b. 8c. 16d. 18e. 245. Which of <strong>the</strong> following is <strong>the</strong> correct “Valence Shell” electron configuration for Ga, using<strong>the</strong> short hand method?a. [Ar] 4d 10 4s 2 4p 1b. [Ar] 3d 10 4s 2 4p 1c. [Ar] 3d 10 4s 2 4p 2d. [Kr] 3d 10 4s 2 4p 1e. [Ar] 4s 2 3d 10 4p 16. How any grams of B are required to produce 12 grams of C, assuming A is present in excess?a. 12 gb. 13.71 gc. 4.67 gd. 10.5 ge. 30.86 gA + 3 B 2 CCompound A B CGrams (g) -- ? 12molar mass (g/mol) 40 72 42
7. What are <strong>the</strong> spectator ions when palladium (II) oxide and nitric acid react?a. Pd +2 & NO 3-b. H + & NO 3-c. H +d. NO 3-e. None of <strong>the</strong> above8. Which one of <strong>the</strong> following sets of quantum numbers ARE ALLOWED?a. I onlyb. II onlyc. I & IV onlyd. II & III onlye. I, II & III onlyn l m lI. 2 0 2II. 3 1 -1III. 5 1 +1IV. 4 4 +29. Calculate <strong>the</strong> energy (J) for ONE quantum of electromagnetic radiation, which has awavelength of 314 nm.a. 6.93 x 10 -33 Jb. 2.08 x 10 -22 Jc. 2.08 x 10 -40 Jd. 6.33 x 10 -17 Je. 6.33 x 10 -19 J10. An aqueous solution of potassium phosphate, K 3 PO 4 , REACTS with an aqueous solution ofiron (III) nitrate, Fe(NO 3 ) 3 . Which one of <strong>the</strong> following represents <strong>the</strong> NET IONICequation for <strong>the</strong> reaction?K 3 PO 4 (aq) + Fe(NO 3 ) 3 (aq) a. K + (aq) + NO 3 - (aq) KNO 3 (aq)b. K 3 PO 4 (aq) + 2 Fe(NO 3 ) 3 (aq) Fe 2 PO 4 (s) + 3 KNO 3 (aq)c. Fe +3 (aq) + PO 4 -3 (aq) FePO 4 (s)d. 2 Fe +2 (aq) + PO 4 -3 (aq) Fe 2 PO 4 (s)e. None of <strong>the</strong> above are correct.
11. Indicate which of <strong>the</strong> following is CORRECT with regard to size and shape of an orbital andits corresponding quantum numbers, n and l:a. I onlyb. II onlyc. III onlyd. II and III onlye. All are incorrect.I. n = 1 and l = 0 represents <strong>the</strong> 1s orbitalII. n = 3 and l = 2 represents <strong>the</strong> 3p orbitalIII. n = 3 and l = 3 represents <strong>the</strong> 3f orbital12. What is <strong>the</strong> short hand electron configuration for <strong>the</strong> Cr?a. [Ar]4s 2 4d 4b. [Ar]4s 2 3d 4c. [Ar]4s 1 3d 5d. [Kr]4s 2 3d 4e. [Kr]4s 1 3d 513. A student used 22.5 mL of 0.80 M KOH to titrate 30 mL of a citric acid, H 3 C 6 H 5 O,solution. How many grams of citric acid were present in <strong>the</strong> sample?Use MM of citric acid as 192 g/mola. 1.152 gb. 3.456 gc. 10.37 gd. 0.094 ge. 8.845 g3 KOH (aq) + H 3 C 6 H 5 O (aq) K 3 C 6 H 5 O (aq) + 3 H 2 O(l)14. What is <strong>the</strong> correct “long form” electronic configuration for Fe?a. 1s 2 2s 2 2p 6 3s 2 3p 6 4s 1 3d 5b. 1s 2 2s 2 2p 6 3s 2 3p 6 4s 1 3d 7c. 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 7d. 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 5e. 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 6
15. Based on “orbital” configuration, how many unpaired electrons are <strong>the</strong>re in <strong>the</strong> highestoccuping orbital/subshell for <strong>the</strong> chlorine atom?a. 0b. 1c. 2d. 5e. None of <strong>the</strong> above.16. Which of <strong>the</strong> following statements is (are) TRUE?I. The 1s orbital is higher in energy than <strong>the</strong> 3d orbital.II. The p orbital only has 2 orientations.III. The s orbital only has 1 orientation.a. I onlyb. II onlyc. III onlyd. I & II onlye. All are True.17. Calculate <strong>the</strong> number of milliliters (ml) that are required to contain 80 grams of chromium(III) nitrate in an 1.0 M solution.a. 367 mlb. 336 mlc. 702 mld. 354 mle. 452 ml18. Which of <strong>the</strong> following is (are) weak electrolytes in water?a. I onlyb. II onlyc. III onlyd. I & III onlye. I, III & IV onlyI. NH 3II. CO 2III. H 2 CO 3IV. HF
19. You are a student worker assigned to make solutions in <strong>the</strong> first floor stockroom of ChoppinHall for <strong>the</strong> CHEM 1212 labs. Mr. Roya Hughes needs you to make 2.0 L of0.20 M KOH solution. How many grams of KOH will you require?a. 224.4 gb. 5.610 gc. 22.44 gd. 56.10 ge. 0.045 g20. How many milliliters of 10.0 M KOH solution are required to make 1.0 liter of a 0.05 Msolution?a. 5 mlb. 200 mlc. 5 x 10 -3 mld. 1000 mle. 1 ml21. An 20 ml of unknown molarity of H 2 CO 3 requires 40 ml of an 0.1M KOH solution at <strong>the</strong>equivalence point. What is <strong>the</strong> molarity of H 2 CO 3 ?a. 1 Mb. 0.1 Mc. 0.2 Md. 0.4 Me. 3 MH 2 CO 3 (aq) + 2 KOH (aq) → K 2 CO 3 (aq) + 2 H 2 O (l)22. What is <strong>the</strong> short hand electron configuration for <strong>the</strong> As?a. [Kr]4s 2 4d 10 4p 3b. [Xe]5s 2 4d 10 4p 3c. [Ar]5s 2 4d 10 5p 3d. [Kr]4s 2 3d 10 4p 3e. [Ar]4s 2 3d 10 4p 3
23. Which orbital is described by <strong>the</strong> shape below?a. sb. pc. dd. fe. None24. What is <strong>the</strong> molecular equation for when ammonium carbonate and tungsten (IV) nitratereact?a. 2 CO 3 -2 (aq) + Ta +4 (aq) Ta(CO 3 ) 2 (s)b. (NH 4 ) 2 CO 3 (aq) + W(NO 3 ) 4 (aq) WCO 3 (s) + 2 NH 4 NO 3 (aq)c. 2 (NH 4 ) 2 CO 3 (aq) + Ta(NO 3 ) 4 (aq) Ta(CO 3 ) 2 (s) + 4 NH 4 NO 3 (aq)d. 2 (NH 4 ) 2 CO 3 (aq) + W(NO 3 ) 4 (aq) W(CO 3 ) 2 (s) + 4 NH 4 NO 3 (aq)e. None of <strong>the</strong> above.25. Who am I? This person hypo<strong>the</strong>sized that Energy must be emitted or absorbed in discretepackets or quanta and <strong>the</strong> energy for each quanta is proportional to its frequency times someconstant.a. Plankb. Einsteinc. Bohrd. Younge. Maxwell26. BONUS: There is a spill of 500 ml of 10.0 M HNO 3 ! How many grams of CaCO 3 will youneed to neutralize this spill?CaCO 3 (s) + 2 HNO 3 (aq) → Ca(NO 3 ) 2 (aq) + H 2 O (l) + CO 2 (g)a. 1 gb. 100 gc. 250 gd. 500 ge. 1000 g