12.07.2015 Views

Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

96defΦ= ( QP A µ Q)◦(QP σ A Q ) ◦ (τP Q) ◦ (A µ Q P Q ) ◦ (AiQ) ◦ ( A C ρ Q)(61),(82)= ( QP µ B Q)◦(QP QσB ) ◦ (τP Q) ◦ (A µ Q P Q ) ◦ (Aτ)τ= ( QP µ B Q)◦ (τB) ◦(QσB ) ◦ (A µ Q P Q ) ◦ (Aτ)A µ Q=(QP µBQ)◦ (τB) ◦( Aµ Q B ) ◦ ( AQσ B) ◦ (Aτ)(70)= ( QP µ B Q)◦ (τB) ◦( Aµ Q B ) ◦ (AQu B )A µ Q=(QP µBQ)◦ (τB) ◦ (QuB ) ◦ A µ Q τ = ( QP µ B Q)◦ (QP QuB ) ◦ τ ◦ A µ QQmodfun= τ ◦ A µ Q(61)= (iQ) ◦ C ρ Q ◦ A µ Qand since by c<strong>on</strong>structi<strong>on</strong> iQ is a m<strong>on</strong>omorphism we get that(C A µ Q)◦ (ΦQ) ◦(A C ρ Q)= C ρ Q ◦ A µ Q .By Lemma 5.3 we know that( )C A µ Q ◦ (ΦQ) = A µ CQso that we getA µ CQ ◦ ( A C ρ Q)=(C A µ Q)◦ (ΦQ) ◦(A C ρ Q)= C ρ Q ◦ A µ Q .Hence there exists a morphism eC ρ A Q : A Q → ˜C A Q such thatAU eC ρ A Q = C ρ Q .By the coassociativity and counitality(properties)of C ρ Q , we deduce that eC ρ A Q isalso coassociative and counital so that AQ, eC ρ A Q is a left ˜C-comodule functor. □Lemma 6.17. Let M = (A, B, P, Q, σ A , σ B ) be a formal dual structure where theunderlying functors are A : A → A, B : B → B, P : A → B and Q : B → A.Assume that both categories A and B have coequalizers and the functors A, QBpreserve them. Assume thatand• C = ( C, ∆ C , ε C) is a com<strong>on</strong>ad <strong>on</strong> the category A such that C preservescoequalizers• ˜C(= ˜C, ∆C e, ε e )Cis a lifting of the com<strong>on</strong>ad of C to the category A A( )• AQ, eC ρ A Q is a left ˜C-comodule functor where A U eC ρ A Q = C ρ Q .C<strong>on</strong>sider the functorial morphismscan 1 := ( Cσ A) ◦ (C ρ Q P ) : QP → CA( ) ( )Acan A := ˜CA σAA eC◦ ρ A QP A : A QP A → ˜CThen can 1 is an isomorphism if and <strong>on</strong>ly if A can A is an isomorphism.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!