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Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

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defd ϕ=(ε C CX ) ◦ (ϕCX) ◦ (LαX) ◦ ( Ld ϕ(X, C ρ X))defα= ( ε C CX ) ◦ (ϕCX) ◦ (LRϕX) ◦ (LηRX) ◦ ( Ld ϕ(X, C ρ X))ϕ= ( ε C CX ) ◦ (ϕϕX) ◦ (LηRX) ◦ ( ( ))Ld ϕ X, C ρ X(ε C CX ) ◦ ( ∆ C X ) ◦ (ϕX) ◦ ( ( ))Ld ϕ X, C ρ Xϕmorphcom<strong>on</strong>ads=so that we deduce thatCcom<strong>on</strong>ad= (ϕX) ◦ ( Ld ϕ(X, C ρ X))C ρ X ◦ (C Ûɛ ( X, C ρ X))= (ϕX) ◦(Ldϕ(X, C ρ X))71and thus( CUγ C) ◦ (C Ûɛ ) = ( ϕ C U ) ◦ Ld ϕ .Let us calculate(∆C C U ) ◦ ( ϕ C U ) ϕcom<strong>on</strong>admorph (= ϕϕ C U ) ◦ ( LηR C U )= ( ϕC C U ) ◦ ( LRϕ C U ) ◦ ( LηR C U ) defα= ( ϕC C U ) ◦ ( Lα C U ) .Theorem 4.53 ([GT] Theorem <str<strong>on</strong>g>2.</str<strong>on</strong>g>6). Let (L, R) be an adjuncti<strong>on</strong> where L : B → Aand R : A → B, let C = ( C, ∆ C , ε C) be a com<strong>on</strong>ad <strong>on</strong> a category A and let ϕ : LR =(LR, LηR, ɛ) → C = ( C, ∆ C , ε C) be a com<strong>on</strong>ad morphism. Let α = Θ (ϕ) = (Rϕ) ◦(ηR) and assume that, for every ( ) ( )X, C ρ X ∈ C A, there exists Equ B αX, R C ρ X .Then we can c<strong>on</strong>sider the functor K ϕ = Υ (ϕ) : B → C A and its right adjointD ϕ : C A → B. D ϕ is full and faithful if and <strong>on</strong>ly if1) L preserves the equalizer(D ϕ , d ϕ ) = Equ Fun(α C U, R C Uγ C) .2) ϕ : LR → C is a com<strong>on</strong>ad isomorphism.Proof. Recall that, by Corollary 4.50,(50)C Ûɛ C F = ϕ.By Corollary 4.51, D ϕ is full and faithful if and <strong>on</strong>ly if ̂ɛ is a functorial isomorphism.Let us assume that ̂ɛ is a functorial isomorphism, hence ϕ is an isomorphism too.Recall that, by Lemma4.52, we have((51)CUγ C) ◦ (C Ûɛ ) = ( ϕ C U ) ◦ (Ld ϕ )so that(52)Let us c<strong>on</strong>sider the diagramC Uγ C = ( ϕ C U ) ◦ (Ld ϕ ) ◦ (C Ûɛ −1) .d ϕLD ϕLR C U LRC Uγ C LRC C ULα C U□

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