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Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

Contents 1. Introduction 2 2. Preliminaries 4 2.1. Some results on ...

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252Propositi<strong>on</strong> A.12 ([ELGO2, Propositi<strong>on</strong> <str<strong>on</strong>g>1.</str<strong>on</strong>g>2]). Let C be an A-coring. Then thefollowing are equivalent(a) A C is flat.(b) (Mod-A) C is an abelian category and the forgetful functor U : (Mod-A) C →Mod-A is left exact (and hence exact).(c) (Mod-A) C is a Grothendieck category and the forgetful functor U : (Mod-A) C →Mod-A is left exact (and hence exact).Proof. By Lemma A.10, the category (Mod-A) C has coproducts and cokernels.(a) ⇒ (c) By Lemma A.11 has kernels. C<strong>on</strong>sider the following diagram( ) Ker (f) , ρKer(f) k() M, ρMf ( ) N, ρNχ ( ) Coker (f) , ρCoker(f)χ ′ ρ k′( ) ( )Coker (k) , ρCoker(k) Ker (χ) , ρKer(χ).¯fin (Mod-A) C . Then we get the diagramKer (f)k M χ ′ Coker (k)fρ¯f Nk ′ Ker (χ) .χ Coker (f)in Mod-A. Since Mod-A is preabelian, f is an isomorphism in Mod-A and hence alsoin (Mod-A) C . Thus also the category (Mod-A) C is preabelian and moreover abelian(there exist products of every finite family of objects in the category). Moreover,by Lemma A.10 and Lemma A.11 U is left exact. Further, the direct limits areexacts for module categories and thus also for (Mod-A) C . We now have to find agenerator for (Mod-A) C . Let ( M, ρ M) ∈ (Mod-A) C and let p : A (M) → M is theusual epimorphism of right A-modules. Let us c<strong>on</strong>sider the epimorphism l given bythe following compositel : C (M) −→ A (M) ⊗ A C p⊗ AC−→ M ⊗ A C −→ 0where the first arrow is the can<strong>on</strong>ical isomorphism and the sec<strong>on</strong>d <strong>on</strong>e is the usualepimorphism so that l ( (c m ) m∈M)=∑m∈M m ⊗ A c m where c m are almost all zero.Then we have the following diagramρ0Pgρ M0MC (M) l M ⊗ A C 00

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