Roller Chain - Tsubaki

Drive Chain SelectionProcedure 3: (Continued)Starting torque: Ts = 43.40 lbs.ftChain tension from starting torqueFms = Ts × i ×3014× 1000/(d/2)30= 43.4 × 60 × × 12/(6.74/2)14= 19866 lbs.Stalling torque: Tb = 52.8 lbs.ftChain tension from stalling torque30dFmb = Tb × i × × 1000 × 1.2/14( 2 )30= 52.8 × 60 × × 12 × 1.2/(6.74/2)14Starting torque: Ts = 6.0 (kgf·m)Chain tension from starting torqueFms = Ts × i ×3014× 1000/(d/2)30= 6.0 × 60 × × 1000/(171.22/2)14= 9011(kgf)Stalling torque: Tb = 7.2 (kgf·m)Chain tension from stalling torqueFmb = Tb × i ×3014× 1000 × 1.2/(d/2)30= 7.2 × 60 × × 1000 × 1.2/(171.22/2)14Drive Chain= 28607 lbs.= 12976 (kgf)Use the greater value of F mb to calculate chain tension as F mb > F ms .Design chain tensionDesign chain tensionF’mb = Fmb × K × Kv × Kc × Ku= 28607 × 0.23 × 1.02 × 1.28 × 0.6= 5154 lbs…………………………………F’mb = Fmb × K × Kv × Kc × Ku= 12976 × 0.23 × 1.02 × 1.28 × 0.62 = 2338 (kgf) ………………………………. 2Procedure 4: Calculate the chain tension from motoracceleration and deceleration.Procedure 4: Calculate the chain tension from motoracceleration and deceleration.Working torqueTs + TbTm = =2= 47.74 lbs.ft43.4 + 52.082Working torqueTs + TbTm = =2= 6.6 (kgf·m)6.0 + 7.22Load torqueT l==W × d2 × 12 × i6613 × 6.742 × 12 × 60 × 3014= 14.5 lbs.ftLoad torqueW × dT l=2 × 1000 × i=3000 × 171.222 × 1000 × 60 × 3014= 2.0 (kgf·m)Motor acceleration time(Im + I l) × n11230 × (Tm – T l)(1.42 + 0.12318) × 1500=1230 × (47.74 - 14.45)ts =Motor deceleration timetb == 0.054 (s)=(Im + I l) × n11230 × (Tm + T l)(1.42 + 0.12318) × 15001230 × (47.74 + 14.45)= 0.029 (s)Motor acceleration timets = (GD2 m + GD 2 l) × n1375× (Tm – T l)(0.06 + 0.00519) × 1500=375 × (6.6 – 2.0)Motor deceleration timetb == 0.057 (s)=(GD 2 m + GD 2 l) × n1375 × (Tm + T l)(0.06 + 0.00519) × 1500375 × (6.6 + 2.0)= 0.030 (s)Because t b is smaller than t s , chain tension from motor deceleration F b is greater than that of acceleration, so F b should be used.Chain tension from accelerationFb =M × V+ FWtb × 60 × 1000=6613 × 20.34+ 66130.029 × 60 × 32.17= 9015 lbs.Chain tension from accelerationFb =W × V+ FWtb × 60 × G3000 × 6.2=+ 30000.030 × 60 × G= 4054 (kgf)A-103