12.07.2015 Views

Electrostatic Fields in Matter

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7 Permittivity and SusceptibilityThe permittivity (and dielectric constant) are related to the susceptibility.For simplicity we consider the case of a constant field, as foundbetween parallel plates. We can then omit the vector nature of thefield.From Gauss’s lawUs<strong>in</strong>g (9) and (4):E = σ f − Pɛ 0E = σ f − σ bɛ 0(13)= σ f − ɛ 0 χ e Eɛ 0giv<strong>in</strong>g E = σ fɛ 011 + χ e(14)The field is reduced by the factor χ e + 1. The capacitance is<strong>in</strong>creased by the same factor. Keep<strong>in</strong>g <strong>in</strong> m<strong>in</strong>d the def<strong>in</strong>ition of thedielectric constant, we have:K = ɛ r = χ e + 1 (15)The permittivity of a dielectric is : ɛ = ɛ r ɛ 0Equation (14) could be written <strong>in</strong> a variety of ways:E =σ fɛ 0 (1 + χ e ) = σ f= σ fɛ r ɛ 0 ɛ(16)Equation (16) illustrates an important po<strong>in</strong>t. In dielectrics it isusually possible to use the normal equations for calulat<strong>in</strong>g electricfields due to free charges by replac<strong>in</strong>g ɛ 0 by ɛ.8

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