12.07.2015 Views

Electrostatic Fields in Matter

Electrostatic Fields in Matter

Electrostatic Fields in Matter

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

2. For a sheet of charge, with charge per unit area of σ, Gauss’slaw gives the field as σ/ɛ 0 .So E free = σ fɛ 0= 4.07 × 10 3 Vm −1and E bound = σ bɛ 0= 2.27 × 10 3 Vm −13. The polarisation ⃗ P is def<strong>in</strong>ed as the total dipole moment per unitvolume. In order to calculate ⃗p, the moment of an <strong>in</strong>dividualdipole, we would need to know the number of dipoles per unitvolume.12

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!