Electrostatic Fields in Matter
Electrostatic Fields in Matter
Electrostatic Fields in Matter
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2. For a sheet of charge, with charge per unit area of σ, Gauss’slaw gives the field as σ/ɛ 0 .So E free = σ fɛ 0= 4.07 × 10 3 Vm −1and E bound = σ bɛ 0= 2.27 × 10 3 Vm −13. The polarisation ⃗ P is def<strong>in</strong>ed as the total dipole moment per unitvolume. In order to calculate ⃗p, the moment of an <strong>in</strong>dividualdipole, we would need to know the number of dipoles per unitvolume.12