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SN Component T TF* B D* X XXAura1. ELi 11 10 0 0 12 122. EMi 14 14 16 16 6 03. E d/p 0 0-1 0 0 10 464. E o/r(+ve) -6 -11 0 -6 -2 05. E Tr 2 0 0 0 0 06. Sum EA (Shah) 21.5 14-15 17.5 10* 18.5 14.57. Energy 1 0.9 1.3 4Density (De*)8. E A (Mehta)* 21 16 24 58* Predicted figuresFurther experiments are needed with sophisticated equipments to quantify thesedeductive statements.For the aforesaid data, following equations should hold good (Mehta).i) E t= E 8+ E b---------------------- ii) i.e., Total energy of a water sample.ii) E t(d)= E g(d)+ E b(d)--------- iii) for distilled wateriii) E t(h)= E g(h)+ E b(h)--------- iv) for dynamised water4.6.2 Dynamisation :It is expected that dynamisation would enhance the good energy and reduce the badenergy of the original sample of a remedy in distilled water. That means,E t(h)> E t(d)andE b(h)< E b(d)Similarly, the total energy of a sample should normally increase by dynamisation process(column iv in Table 9), say by 20% . Then the above functions can be expressed as :Et(h) = 1.2Et(d) and Eb(h) = 0.8Eb(d)With this data, the above equation at (iv) can be rewritten as follows :1.2E t(d)= E g(h)+ 0.8E b(d)i.e. E g(h)= 1.2 E t(d)- 0.8 E b(d)----------- (v)and the equation (iii) can be rewritten asE g(d)= E t(d)- E b(d)---------------- (vi)and thusE g(h)becomse >> E g(d)4.7.1 Following difference in Shah & Mehta’s “aura” should be kept in mind.i) The total E (A) area (Shah) represents the area of ‘surrounding aura energy’ onlyand not the energy on the ‘body’ of the object.ii) Mehta’s ‘good energy’ (Eg) represents the area of good colors (blue, white etc) onthe body of the object as well as in the “surrounding aura energy” in his photographs of aura.iii) His is only qualitative assessment of good energy.4.7.2 An attempt has been made to co-relate the Shah’s energy area E (A) with the88Arhat Vacana, 23 (1-2), 2011