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Quasilinear parabolic problems with nonlinear boundary conditions

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and<br />

Z T ∇ = H 1<br />

2 (1+α)<br />

p<br />

Y T 1<br />

(1+α)(1− 2p<br />

D = B )<br />

pp<br />

Y T 1 1<br />

(1+α)( − 2 2p<br />

N = B )<br />

pp<br />

2− 2<br />

p(1+α)<br />

Y0 = Bpp (Ω), Y1 = B<br />

(J; Lp(Ω)) ∩ Lp(J; H 1 p(Ω)),<br />

2− 1<br />

p<br />

(J; Lp(ΓD)) ∩ Lp(J; Bpp (ΓD)), (6.3)<br />

1− 1<br />

p<br />

(J; Lp(ΓN)) ∩ Lp(J; Bpp (ΓN)), (6.4)<br />

2 2<br />

2− − 1+α p(1+α)<br />

pp<br />

α > 1/p being assumed in the definition of Y1. For Λ ∈ {ZT , ZT ∇ , Y T D , Y T N , XT 1 ), we as<br />

usual denote by 0Λ the subspace of all functions h ∈ Λ <strong>with</strong> h|t=0 = 0 and ∂th|t=0 = 0,<br />

in case that these traces exist.<br />

If u ∈ ZT , then this corresponds, as we know from Theorem 4.3.1, to the regularity<br />

classes<br />

(Ω),<br />

∇u ∈ (Z T ∇) n , ∇ 2 u ∈ (X T ) n×n , γDu ∈ Y T D , γN∇u ∈ (Y T N ) n , u|t=0 ∈ Y0, ∂tu|t=0 ∈ Y1.<br />

Consequently, Y0 is the natural space for u0, and if α > 1/p and u ∈ Z T is a solution of<br />

(6.1), then we have to ensure that u1 := ∂tu|t=0, which is given by<br />

u1(x) = f(0, x, u0(x), ∇u0(x)), x ∈ Ω,<br />

belongs to Y1. Of course, we have to assume that<br />

Observe also that<br />

as well as<br />

u0(x) ∈ U0, ∇u0(x) ∈ U1, x ∈ Ω. (6.5)<br />

Z T ↩→ C(J; Y0) ↩→ C(J × Ω)<br />

Z T 2<br />

1− p(1+α)<br />

∇ ↩→ C(J; Bpp (Ω)) ↩→ C(J × Ω),<br />

provided that 1 − 2/p(1 + α) > n/p, which is equivalent to<br />

p > 2<br />

1+α + n (6.6)<br />

and which will be assumed throughout this section.<br />

Notice further that we have to take into account the three compatibility <strong>conditions</strong><br />

b D (0, x, u0(x)) = 0, x ∈ ΓD,<br />

b N (0, x, u0(x), ∇u0(x)) = 0, x ∈ ΓN,<br />

b D t (0, x, u0(x)) + b D ξ (0, x, u0(x))u1(x) = 0, x ∈ ΓD, if α > 3<br />

2p−1 .<br />

Here and in the subsequent lines we assume that b D and b N are as smooth as needed to<br />

make the formulas meaningful. Precise regularity statements will be given later on.<br />

We now set out to reformulate (6.1) as a fixed point problem in an appropriate subset<br />

of Z T . To this end, we first put<br />

A0(x) = −a(0, x, u0(x), ∇u0(x)), x ∈ Ω.<br />

Further we fix a function φ ∈ Z T0 which satisfies φ|t=0 = u0 and ∂tφ|t=0 = u1, the latter<br />

being demanded in case that α > 1/p. In view of (6.5) and (6.6), we see that, for T<br />

96

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