Quasilinear parabolic problems with nonlinear boundary conditions
Quasilinear parabolic problems with nonlinear boundary conditions
Quasilinear parabolic problems with nonlinear boundary conditions
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where δij denotes Kronecker’s symbol. The function a describes how the material responds<br />
to shear, while b determines its behaviour under compression. Therefore, a is<br />
called shear modulus and b compression modulus. The constitutive law (5.7) becomes<br />
� ∞<br />
S(t, x) = 2<br />
0<br />
0<br />
da(τ, x) ˙<br />
E(t − τ, x) + 1<br />
3 I<br />
0<br />
� ∞<br />
(3db(τ, x) − 2da(τ, x))tr ˙ E(t − τ, x).<br />
Besides, we want to assume that the material is homogeneous, i.e. ρ0 as well as a and<br />
b do not depend on the material points x ∈ Ω. For simplicity, let us put ρ0(x) ≡ 1, x ∈ Ω.<br />
To summarize, we obtain the following integro-differential equation for homogeneous<br />
and isotropic materials:<br />
� ∞<br />
� ∞<br />
ü(t, x) = da(τ)∆ ˙u(t − τ, x) + (db(τ) + 1<br />
da(τ))∇∇ · ˙u(t − τ, x) + f(t, x), (5.10)<br />
3<br />
for all t ∈ R and x ∈ Ω. This equation has to be supplemented by the <strong>boundary</strong><br />
<strong>conditions</strong> (5.3),(5.4).<br />
Let us consider a material which is at rest up to time t = 0, but is then suddenly<br />
moved <strong>with</strong> the velocity v0(x), x ∈ Ω. More precisely, we want to assume that v(t, x) =<br />
˙u(t, x) = 0, t < 0, x ∈ Ω, and v(0, x) = v0(x), x ∈ Ω. Then the problem (5.10),(5.3),(5.4)<br />
amounts to<br />
⎧<br />
⎪⎨<br />
⎪⎩<br />
∂tv − da ∗ ∆v − (db + 1<br />
3da) ∗ ∇∇ · v = f, t > 0, x ∈ Ω<br />
(2da ∗ ˙<br />
E + 1<br />
3<br />
I(3db − 2da) ∗ tr ˙<br />
0<br />
v = vd, t > 0, x ∈ Γd<br />
E) n = gs, t > 0, x ∈ Γs<br />
v|t=0 = v0, x ∈ Ω,<br />
where we use the notation (dk ∗ φ)(t) = � t<br />
0 dk(τ)φ(t − τ), t > 0.<br />
(5.11)<br />
5.2 Assumptions on the kernels and formulation of the goal<br />
Given f, vd, gs, v0, our goal is to solve (5.11) for v. For this to be possible it is necessary<br />
that the convolution terms in (5.11) do not produce terms involving the displacement u,<br />
which would be the case, if for example a(t) = t, t ≥ 0. That means the problem must<br />
not be hyperbolic. Further we need certain regularity assumptions on a and b so that<br />
we can apply the results from Section 3.5. It turns out that the following class of kernels<br />
is appropriate for our problem.<br />
Definition 5.2.1 A function k : [0, ∞) → R is said to be of type (E) if<br />
(E1) k(0) = 0, and k is of the form k(t) = k0 + � t<br />
0 k1(τ) dτ, t > 0, where k0 ≥ 0 and<br />
k1 ∈ L1, loc(R+);<br />
(E2) k1 is completely monotonic, i.e. k1 ∈ C∞ (0, ∞) and (−1) lk (l)<br />
1 (t) ≥ 0 for all<br />
t > 0, l ∈ N0;<br />
(E3) if k1 �= 0, then k1 ∈ K∞ π<br />
(α, θk1 ), for some α ∈ [0, 1) and θk1 < 2 .<br />
Observe that (E1) and (E2) imply that the function k in Definition 5.2.1, restricted to<br />
the interval (0, ∞), is a Bernstein function, which by definition means that k is R+valued,<br />
infinitely differentiable on (0, ∞), and that k ′ is completely monotonic. We<br />
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