02.12.2012 Views

Quasilinear parabolic problems with nonlinear boundary conditions

Quasilinear parabolic problems with nonlinear boundary conditions

Quasilinear parabolic problems with nonlinear boundary conditions

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Further, K ∞ (α, θa) := {a ∈ L1, loc(R+) : a ∈ K r (α, θa) for all r ∈ N}. The kernel a is<br />

called a K-kernel if there exist r ∈ N, θa > 0, and α ≥ 0, such that a ∈ K r (α, θa).<br />

An example for a K-kernel is the so-called standard kernel:<br />

Example 2.6.1 (standard kernel) Let a(t) = t α−1 /Γ(α), t > 0, <strong>with</strong> α > 0. Then<br />

a ∈ L1, loc(R+), a is of subexponential growth, and its Laplace transform is given by<br />

â(λ) = λ −α , Re λ > 0. Hence, a ∈ K ∞ (α, α π<br />

2 ).<br />

From [58, p. 4793] it follows that Kr (α, θ) �= ∅ entails the inequality θ ≥ α π<br />

2 . In view of<br />

Example 2.6.1 we thus get the following equivalence:<br />

Remarks 2.6.1 Let α > 0. Then K r (α, θ) �= ∅ if and only if θ ≥ α π<br />

2 .<br />

The subsequent lemma collects some important algebraic properties of K-kernels.<br />

Lemma 2.6.2 Suppose a ∈ K r (α, θa), b ∈ K s (β, θb), and ω > 0. Let aω be defined by<br />

aω(t) = a(t)e −ωt , t ≥ 0. Then the following statements hold true.<br />

(i) aω ∈ K r (α, θa) ∩ L1(R+), and there exist positive constants C1, C2 such that<br />

C1<br />

|λ + ω| α ≤ |âω(λ)| ≤<br />

C2<br />

, Re λ > 0. (2.19)<br />

|λ + ω| α<br />

(ii) If a and b satisfy (2.18), then a + b ∈ K min{r,s} (min{α, β}, max{θa, θb}).<br />

(iii) a ∗ b ∈ K min{r,s} (α + β, θa + θb).<br />

(iv) If α > β and lim infµ→0 |â(µ)/ ˆ b(µ)| > 0, then there exists a unique kernel c ∈<br />

K min{r,s} (α − β, θa + θb) such that a = b ∗ c. If in addition Im â(λ)·Im ˆ b(λ) ≥ 0 for<br />

all Re λ > 0, then c ∈ K min{r,s} (α − β, max{θa, θb}).<br />

(v) If α > 0 and θa < π, then there is a unique kernel ξ ∈ K r (α, θa) such that<br />

ξ + ωξ ∗ a = a.<br />

(vi) If a ∈ L1(R+) and ɛ := ω|a| L1(R+) < 1, then there is a unique kernel ξ ∈ K r (α, θa +<br />

arcsin(ɛ)) ∩ L1(R+) such that ξ − ωξ ∗ a = a.<br />

Proof. Suppose a ∈ K r (α, θa) and ω > 0. Then it is evident that aω lies in L1(R+) and<br />

is of subexponential growth. Further, âω(λ) = â(λ + ω), Re λ > 0. Thus, for all k ∈ N<br />

<strong>with</strong> 1 ≤ k ≤ r and λ ∈ C+,<br />

|λ k â (k)<br />

ω (λ)| = |λ k â (k) (λ + ω)| = |(λ + ω) k â (k) (λ + ω)|<br />

≤ C|â(λ + ω)| = C|âω(λ)|,<br />

� �<br />

�<br />

�<br />

λ �<br />

�<br />

�λ<br />

+ ω �<br />

where C > 0 is the constant of r-regularity of a, i.e. aω is r-regular. We easily see θasectoriality<br />

of aω, too. Moreover, Lemma 2.6.1(v) implies |âω(λ)| ≤ c|âω(|λ|)| for all λ ∈<br />

C+, <strong>with</strong> c not depending on λ. So, owing to continuity and the asymptotic behaviour<br />

of â on R+ described in (K3), there exist two positive constants C1 and C2 such that<br />

|âω(λ)(λ+ω) α | = |â(λ+ω)(λ+ω) α | ∈ [C1, C2] for all Re λ > 0. This shows (2.19). As for<br />

property (K3), by Lemma 2.6.1(ii), we have lim infµ→0 | âω(µ)| = |â(ω)| > 0. The other<br />

23<br />

k

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!