Quasilinear parabolic problems with nonlinear boundary conditions
Quasilinear parabolic problems with nonlinear boundary conditions
Quasilinear parabolic problems with nonlinear boundary conditions
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Given φ, φ ′ ∈ (0, π] we denote by H ∞ (Σφ × Σφ<br />
′) the Banach algebra of all bounded<br />
φ′<br />
holomorphic scalar-valued functions on Σφ × Σφ ′ equipped <strong>with</strong> the norm |f|φ, ∞<br />
sup{|f(λ, λ ′ )| : |arg λ| < φ, |arg λ ′ | < φ ′ }, and we put H0(Σφ × Σφ ′) = {f ∈ H∞ (Σφ ×<br />
Σφ ′) : ∃(f1, f2) ∈ H0(Σφ)×H0(Σφ ′), f1 and f2 non-vanishing, and f(f1f2) −1 ∈ H ∞ (Σφ×<br />
Σφ ′)}. Let A, B ∈ S(X) <strong>with</strong> spectral angles φA and φB, respectively, commute in the<br />
resolvent sense. For φ ∈ (φA, π), φ ′ ∈ (φB, π), and f ∈ H0(Σφ × Σφ<br />
f(A, B) = − 1<br />
4π 2<br />
�<br />
Γψ×Γ ψ ′<br />
′) one defines<br />
:=<br />
f(λ, λ ′ )(λ − A) −1 (λ − B) −1 dλ dλ ′ , (2.12)<br />
where (ψ, ψ ′ ) ∈ (φA, φ) × (φB, φ ′ ). This integral converges in B(X) and does not depend<br />
on the choice of ψ and ψ ′ . Via ΦA, B(f) = f(A, B), it defines a joint functional calculus<br />
ΦA, B : H0(Σφ × Σφ ′) → B(X). In analogy to Definition 2.2.1, we say that (A, B) admits<br />
a bounded joint H∞-calculus (symbolized by (A, B) ∈ H∞ (X)) if there exist φ ∈ (φA, π),<br />
φ ′ ∈ (φB, π), and a constant Kφ, φ ′ < ∞ such that<br />
φ′<br />
|f(A, B)| ≤ Kφ, φ ′|f|φ, ∞ for all f ∈ H0(Σφ × Σφ ′). (2.13)<br />
If (A, B) ∈ H∞ (X), then the functional calculus for (A, B) on H0(Σφ × Σφ ′) extends<br />
uniquely to H∞ (Σφ × Σφ ′).<br />
An interesting question is the following: what are the Banach spaces X for which<br />
(A, B) admits a bounded joint H∞-calculus as soon as A and B, each, admit a bounded<br />
H∞-calculus? In [1] Albrecht was able to prove that this is the case if X = Lp(Ω, Σ, µ),<br />
1 < p < ∞, where (Ω, Σ, µ) is a σ-finite measure space, see also [2, Section 5]. Lancien et<br />
al. [51] extended this result to a class of Banach spaces which enjoy a certain geometric<br />
property. They also give an example for a Banach space not possessing the joint calculus<br />
property. We would further like to mention a result by Kalton and Weis [47] which<br />
asserts, <strong>with</strong>out additional assumption on X, that if A ∈ H∞ (X) and B ∈ RH∞ (X)<br />
<strong>with</strong> commuting resolvents, then (A, B) admits a bounded joint H∞-calculus. We consider now an important example.<br />
Example 2.4.1 Let 1 < p < ∞, X = Lp(R+ × Rn ), and denote the independent variables<br />
by t (∈ R+) resp. x (∈ Rn ). Take B = ∂t <strong>with</strong> domain D(B) = 0H 1 p(R+; Lp(Rn )),<br />
and define A as the natural extension of −∆x in Lp(Rn ) <strong>with</strong> D(−∆x) = H2 p(Rn ) to X,<br />
i.e. D(A) = Lp(R+; H2 p(Rn )) and Af = −∆xf, f ∈ D(A). Then A and B commute in<br />
the resolvent sense, and A, B ∈ H ∞ (X) <strong>with</strong> H ∞ -angles φ ∞ A = 0 resp. φ∞ B<br />
= π/2. Since<br />
X has the joint calculus property, we have (A, B) ∈ H ∞ (X). More precisely, for each<br />
η ∈ (0, π/2), there exists Cη > 0 such that for all f ∈ H ∞ (Ση × Σ π<br />
2 +η), f(A, B) ∈ B(X)<br />
η, π/2+η<br />
and |f(A, B)| B(X) ≤ Cη|f| ∞ .<br />
Regarding functions in X as elements in Lp(R+; Lp(Rn )), the resolvent of B admits<br />
the kernel representation<br />
(λ − B) −1 w(t) = −<br />
� t<br />
0<br />
e λ(t−s) w(s) ds, t ∈ R+,<br />
for all w ∈ X. Thus, for f ∈ H0(Ση × Σ π<br />
2 +η), the operators f(A, B) admit a kernel<br />
representation as well, namely<br />
� �<br />
t �<br />
−1<br />
f(A, B)w(t) =<br />
e<br />
0 2πi Γψ ′<br />
λ′ �<br />
(t−s) ′ ′<br />
f(A, λ )dλ w(s) ds, t ∈ R+. (2.14)<br />
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